numpy.i0() function | Python

numpy.ma.ediff1d() function in Python

Last Updated : 12 Nov, 2020

numpy.ma.ediff1d() function return the differences between consecutive elements of an array.

Syntax : numpy.ma.ediff1d(arr, to_end = None, to_begin = None)

Parameters :
arr : [array_like] Input array.
to_end : [array_like, optional] Number to append at the end of the returned differences.
to_begin : [array_like, optional] Number to prepend at the beginning of the returned differences.

Return : Return the differences between consecutive elements of an array.

Code #1:

Python3

# Python program explaining
# numpy.ma.ediff1d() function

# importing numpy as geek
import numpy as geek

arr = geek.array([3, 5, 8, 4, 12])

gfg = geek.ma.ediff1d(arr)

print(gfg)

Output:

[ 2  3 -4  8]

Code #2:

Python3

# Python program explaining
# numpy.ma.ediff1d() function

# importing numpy as geek
import numpy as geek

arr = geek.array([3, 5, 8, 4, 12])

gfg = geek.ma.ediff1d(arr, to_begin=geek.array([-23, 0]), to_end=25)

print(gfg)

Output:

[-23 0 2 3 -4 8 25]

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