Python | Numpy numpy.matrix.all()

Python | Numpy numpy.matrix.all()

Last Updated : 08 Apr, 2019

With the help of Numpy numpy.matrix.all() method, we are able to compare each and every element of one matrix with another or we can provide the axis on the we want to apply comparison.

Syntax : numpy.matrix.all() Return : Return true if found match else false

Example #1 : In this example we can see that with the help of matrix.all() method, we are able to compare any two matrix having different dimensions.

Python3 1==

# import the important module in python
import numpy as np
        
# make a matrix with numpy
gfg1 = np.matrix('[1, 2, 3, 4]')
gfg2 = np.matrix('[1, 2, 3, 4]')
        
# applying matrix.all() method
geeks = (gfg1 == gfg2).all()
  
print(geeks)

Output:

True

Example #2 :

Python3 1==

# import the important module in python
import numpy as np
        
# make a matrix with numpy
gfg1 = np.matrix('[1, 2, 3; 4, 5, 6; 7, 8, 9]')
gfg2 = np.matrix('[1, 2, 3]')
        
# applying matrix.all() method
geeks = (gfg1 == gfg2).all()
  
print(geeks)

Output:

False

Python | Numpy numpy.matrix.all()

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