How to use catch to handle the exception in Java

Problem Description

How to use catch to handle the exception?

Solution

This example shows how to use catch to handle the exception.

public class Main{
   public static void main (String args[]) {
      int array[] = {20,20,40};
      int num1 = 15, num2 = 10;
      int result = 10;
      try {
         result = num1/num2;
         System.out.println("The result is" +result);
         
         for(int i = 5; i >= 0; i--) {
            System.out.println("The value of array is" +array[i]);
         }
      } catch (Exception e) {
         System.out.println("Exception occoured : "+e);
      }
   }
}

Result

The above code sample will produce the following result.

The result is1
Exception occoured : java.lang.ArrayIndexOutOfBoundsException: 5

The following is an another example of catch to handle the exception in Java

public class Trycatch { 
   public static void main(String args[]) { 
      try { 
         int data = 50/0; 
      } catch(ArithmeticException e){System.out.println(e);}
      System.out.println("rest of the code...");
   }
}

The above code sample will produce the following result.

java.lang.ArithmeticException: / by zero
rest of the code...