Find Frequency of an Element in an Array using Go

Examples

In the Input array, arr = [2, 4, 6, 7, 8, 1, 2]

Frequency of 2 in given array is 2

Frequency of 7 is 1

Frequency of 3 is 0.

Approach to solve this problem

Step 1: Define a function that accepts an array and a num

Step 2: Declare a variable count = 0.

Step 3: Iterate the given array and increase the count by 1 if num occurs in the array.

Step 4: Print count for the given num.

Program

Live Demo

package main
import "fmt"
func findFrequency(arr []int, num int){
   count := 0
   for _, item := range arr{
      if item == num{
         count++
      }
   }
   fmt.Printf("Frequency of %d in given array is %d.\n", num, count)
}

func main(){
   findFrequency([]int{2, 4, 5, 6, 3, 2, 1}, 2)
   findFrequency([]int{0, 1, 3, 1, 6, 2, 1}, 1)
   findFrequency([]int{1, 2, 3, 4, 5, 6, 7}, 10)
}

Output

Frequency of 2 in given array is 2.
Frequency of 1 in given array is 3.
Frequency of 10 in given array is 0.