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Rod Taylor

Australian-American actor (1930-2015)

Shapes:

URI: http://yago-knowledge.org/resource/Rod_Taylor

Graph visualizationOfficial Website
Properties
PredicateObject
schema:alternateName
  • "Robert Taylor"@cs
  • "Rodney Sturt Taylor"@cs
  • "Rodney Taylor"@cs
  • "Rodney Sturt Taylor"@de
  • "Rodney Sturt Taylor"@en
  • "Rodney Sturt Taylor"@es
  • "Rodney Sturt Taylor"@fr
  • "Rodney Sturt Taylor"@hu
  • "Rodney Stuart Taylor"@it
  • "Rodney Taylor Sturt"@pt
schema:alumniOf
schema:birthDate
schema:birthPlace
schema:children
schema:deathDate
schema:deathPlace
schema:gender
schema:image
  • "http://commons.wikimedia.org/wiki/Special:FilePath/Rod%20Taylor%20-%201963.jpg"^^xsd:anyURI
schema:knowsLanguage
schema:mainEntityOfPage
  • "https://af.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://ar.wikipedia.org/wiki/%D8%B1%D9%88%D8%AF_%D8%AA%D8%A7%D9%8A%D9%84%D9%88%D8%B1"^^xsd:anyURI
  • "https://arz.wikipedia.org/wiki/%D8%B1%D9%88%D8%AF_%D8%AA%D8%A7%D9%8A%D9%84%D9%88%D8%B1"^^xsd:anyURI
  • "https://azb.wikipedia.org/wiki/%D8%B1%D8%A7%D8%AF_%D8%AA%DB%8C%D9%84%D9%88%D8%B1"^^xsd:anyURI
  • "https://ca.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://commons.wikimedia.org/wiki/Category:Rod_Taylor"^^xsd:anyURI
  • "https://cs.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://cy.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://de.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://el.wikipedia.org/wiki/%CE%A1%CE%BF%CE%BD%CF%84_%CE%A4%CE%AD%CE%B9%CE%BB%CE%BF%CF%81"^^xsd:anyURI
  • "https://en.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://eo.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://es.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://eu.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://fa.wikipedia.org/wiki/%D8%B1%D8%A7%D8%AF_%D8%AA%DB%8C%D9%84%D9%88%D8%B1"^^xsd:anyURI
  • "https://fi.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://fr.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://hu.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://id.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://it.wikipedia.org/wiki/Rod_Taylor"^^xsd:anyURI
  • "https://ja.wikipedia.org/wiki/%E3%83%AD%E3%83%83%E3%83%89%E3%83%BB%E3%83%86%E3%82%A4%E3%83%A9%E3%83%BC"^^xsd:anyURI
  • ...
schema:sameAs
  • "/m/01q6bg"
  • "nm0001792"
schema:url
rdf:type
rdfs:comment
  • "ممثل أسترالي"@ar
  • "actor australianu"@ast
  • "অস্ট্রেলীয় অভিনেতা"@bn
  • "actor australià"@ca
  • "australsk skuespiller"@da
  • "Australian actor"@en-ca
  • "Australian actor"@en-gb
  • "aŭstralia aktoro"@eo
  • "actor australiano"@es
  • "Austraalia näitleja"@et
  • "aktore australiarra"@eu
  • "بازیگر استرالیایی"@fa
  • "aisteoir Astrálach"@ga
  • "actor australiano"@gl
  • "שחקן אוסטרלי"@he
  • "ator australian"@lfn
  • "australsk skuespiller"@nb
  • "Australisch acteur"@nl
  • "australsk skodespelar"@nn
  • "actor australian"@ro
  • "австралийский актёр"@ru
  • ...
rdfs:label
  • "رود تايلور"@ar
  • "Rod Taylor"@ast
  • "Rod Taylor"@ca
  • "Rod Taylor"@cy
  • "Rod Taylor"@de
  • "Rod Taylor"@en
  • "Rod Taylor"@es
  • "Rod Taylor"@fr
  • "Rod Taylor"@nl
  • "Род Тейлор"@ru
  • "Rod Taylor"@sl
  • "Rod Taylor"@sq
  • "Rod Taylor"@af
  • "رود تايلور"@arz
  • "راد تیلور"@azb
  • "Rod Taylor"@cs
  • "Rod Taylor"@da
  • "Rod Taylor"@de-ch
  • "Ροντ Τέιλορ"@el
  • "Rod Taylor"@en-ca
  • "Rod Taylor"@en-gb
  • ...
Incoming properties
PredicateSubject
schema:actor
schema:performer