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1873 Rhode Island gubernatorial election

From Wikipedia, the free encyclopedia

1873 Rhode Island gubernatorial election

← 1872 2 April 1873 1874 →
 
Nominee Henry Howard Benjamin G. Chace
Party Republican Democratic
Popular vote 9,656 3,786
Percentage 71.68% 28.11%

County results
Howard:      60–70%      70–80%      >90%

Governor before election

Seth Padelford
Republican

Elected Governor

Henry Howard
Republican

The 1873 Rhode Island gubernatorial election was held on 2 April 1873 in order to elect the governor of Rhode Island. Republican nominee Henry Howard defeated Democratic nominee Benjamin G. Chace.[1]

General election

[edit]

On election day, 2 April 1873, Republican nominee Henry Howard won the election by a margin of 5,870 votes against his opponent Democratic nominee Benjamin G. Chace, thereby retaining Republican control over the office of governor. Howard was sworn in as the 32nd governor of Rhode Island on 6 May 1873.[2]

Results

[edit]
Rhode Island gubernatorial election, 1873
Party Candidate Votes %
Republican Henry Howard 9,656 71.68
Democratic Benjamin G. Chace 3,786 28.11
Scattering 29 0.21
Total votes 13,471 100.00
Republican hold

References

[edit]
  1. ^ "Henry Howard". National Governors Association. Retrieved 8 April 2024.
  2. ^ "RI Governor". ourcampaigns.com. 6 October 2005. Retrieved 8 April 2024.