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1967–68 Coupe de France

From Wikipedia, the free encyclopedia
1967–68 Coupe de France
Tournament details
Country France

The Coupe de France's results of the 1967–68 season. AS Saint-Étienne won the final played on May 12, 1968, beating Girondins de Bordeaux.

Round of 16

[edit]
Team 1  Score  Team 2
AS Saint-Étienne (D1) 2–1 Angers SCO (D1)
FC Metz (D1) 2–1 AS Nancy (D2)
AS Angoulême (D2) 2–0 FC Rouen (D1)
FC Sochaux-Montbéliard (D1) 2–1 FC Nantes (D1)
Girondins de Bordeaux (D1) 2–0 Gazélec Ajaccio (CFA)
RC Strasbourg (D1) 0–0 (a.e.t.) Red Star (D1)
US Quevilly (CFA) 1–0 Olympique Lyonnais (D1)
USL Dunkerque (D2) 1–0 OGC Nice (D1)
Replay
RC Strasbourg (D1) 1–0 Red Star (D1)

Quarter-finals

[edit]
Team 1  Score  Team 2
AS Saint-Étienne (D1) 1–0 FC Metz (D1)
AS Angoulême (D2) 2–1 (a.e.t.) FC Sochaux-Montbéliard (D1)
Girondins de Bordeaux (D1) 1–1 (a.e.t.) RC Strasbourg (D1)
US Quevilly (CFA) 4–0 USL Dunkerque (D2)
Replay
Girondins de Bordeaux (D1) 2–1 RC Strasbourg (D1)

Semi-finals

[edit]
AS Saint-Étienne (1)1–1 (a.e.t.)AS Angoulême (2)
Mekhloufi 29' (Report) Grizzetti 33'

Girondins de Bordeaux (1)2–1 (a.e.t.)US Quevilly (3)
Massé 34'
Duhayot 99'
(Report) Leroy 13'

Replay

AS Saint-Étienne (1)2–1AS Angoulême (2)
Herbin 26'
Revelli 70'
(Report) Grizzetti 83'

Final

[edit]
Saint-Étienne2–1Bordeaux
Mekhloufi 30', 78' Report Wojciak 5'

References

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