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import java.util.*;
public class _508 {
//递归写法
static class Solution1 {
public int[] findFrequentTreeSum(TreeNode root) {
// 后序遍历,统计每个节点和的数量
Map<Integer, Integer> sumCount = new HashMap<>();
postOrder(root, sumCount);
TreeMap<Integer, List<Integer>> map = new TreeMap<>();
for (Map.Entry<Integer, Integer> e : sumCount.entrySet()) {
map.computeIfAbsent(e.getValue(), k -> new ArrayList<>()).add(e.getKey());
}
List<Integer> resList = map.lastEntry().getValue();
int[] res = new int[resList.size()];
int idx = 0;
for (int val : resList) {
res[idx++] = val;
}
return res;
}
public int postOrder(TreeNode root, Map<Integer, Integer> sumCount) {
if (root == null) return 0;
int cur = root.val + postOrder(root.left, sumCount) + postOrder(root.right, sumCount);
int count = sumCount.getOrDefault(cur, 0);
sumCount.put(cur, count + 1);
return cur;
}
}
//非递归写法难度很高
static class Solution2 {
public int[] findFrequentTreeSum(TreeNode root) {
if (root == null) return new int[0];
Deque<TreeNode> dq = new ArrayDeque<>();
Map<Integer, Integer> map = new HashMap<>();
Map<TreeNode, Integer> cache = new HashMap<>();//缓存左右子树的和
TreeNode lastPop = new TreeNode();
int lastSum = 0;
//左节点不为空入栈,当前节点为结点
//右节点不为空入栈,当前节点为右结点
//上个弹出的为右结点,下个弹出的为当前结点
//上个弹出的节点为左结点,且右节点为空,弹出当前结点,右结点不为空,右结点入栈
dq.push(root);
while (!dq.isEmpty()) {
TreeNode top = dq.peek();
if ((top.left == lastPop && top.right == null) || (top.right == lastPop) || (top.left == null && top.right == null)) {
lastPop = dq.pop();
lastSum = lastPop.val + cache.getOrDefault(lastPop, 0);
map.put(lastSum, map.getOrDefault(lastSum, 0) + 1);
TreeNode next = dq.peek();
if (next != null) {
int last = cache.getOrDefault(next, 0);
cache.put(next, last + lastSum);
}
continue;
}
if (top.left != null && top.left != lastPop) {
dq.push(top.left);
} else if ((top.left == lastPop || top.left == null) && top.right != null) {
dq.push(top.right);
}
}
int maxVal = 0;
for (int value : map.values()) {
maxVal = Math.max(value, maxVal);
}
List<Integer> res = new ArrayList<>();
for (Map.Entry<Integer, Integer> entry : map.entrySet()) {
if (entry.getValue().equals(maxVal)) {
res.add(entry.getKey());
}
}
int[] r = new int[res.size()];
int idx = 0;
for (int v : res) {
r[idx++] = v;
}
return r;
}
}
}
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