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A014160
Apply partial sum operator thrice to partition numbers.
6
1, 4, 11, 25, 51, 96, 171, 291, 478, 762, 1185, 1803, 2693, 3956, 5727, 8182, 11552, 16134, 22313, 30579, 41559, 56045, 75039, 99796, 131891, 173282, 226405, 294270, 380595, 489945, 627924, 801374, 1018644
OFFSET
0,2
COMMENTS
A014160 convolved with A010815 = A000217, the triangular numbers. - Gary W. Adamson, Nov 09 2008
Unordered partitions of n into parts where the part 1 comes in 4 colors. - Peter Bala, Dec 23 2013
From Omar E. Pol, Mar 01 2023: (Start)
Partial sums of A014153.
Convolution of A000070 and A000027.
Convolution of A000041 and the positive terms of A000217.
Convolution of A002865 and the positive terms of A000292. (End)
LINKS
FORMULA
From Peter Bala, Dec 23 2013: (Start)
O.g.f.: 1/(1 - x)^3 * Product_{k >= 1} 1/(1 - x^k).
a(n-1) + a(n-2) = Sum_{parts k in all partitions of n} J_2(k), where J_2(n) is the Jordan totient function A007434(n). (End)
a(n) ~ 3*sqrt(n) * exp(Pi*sqrt(2*n/3)) / (sqrt(2)*Pi^3). - Vaclav Kotesovec, Oct 30 2015
a(n) = Sum_{k=0..n} A014153(k). - Sean A. Irvine, Oct 14 2018
MATHEMATICA
nmax = 50; CoefficientList[Series[1/((1-x)^3 * Product[1-x^k, {k, 1, nmax}]), {x, 0, nmax}], x] (* Vaclav Kotesovec, Oct 30 2015 *)
CROSSREFS
Cf. A010815, A000217. - Gary W. Adamson, Nov 09 2008
Column k=4 of A292508.
Sequence in context: A011851 A193912 A136395 * A014162 A014169 A113684
KEYWORD
nonn
STATUS
approved