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A116845
Number of permutations of length n which avoid the patterns 231, 12534.
1
1, 2, 5, 14, 41, 121, 355, 1032, 2973, 8496, 24111, 68017, 190885, 533294, 1484021, 4115186, 11375765, 31358377, 86223943, 236540916, 647556621, 1769374932, 4826148315, 13142564449, 35736448201, 97037995226, 263156279525, 712795854422, 1928547574913
OFFSET
1,2
LINKS
Jean-Luc Baril, Toufik Mansour, José L. Ramírez, and Mark Shattuck, Catalan words avoiding a pattern of length four, Univ. de Bourgogne (France, 2024). See p. 3.
Giulio Cerbai, Anders Claesson, and Luca Ferrari, Stack sorting with restricted stacks, arXiv:1907.08142 [cs.DS], 2019.
Guo-Niu Han, Enumeration of Standard Puzzles, arXiv:2006.14070 [math.CO], 2020.
Guo-Niu Han, Enumeration of Standard Puzzles. [Cached copy]
FORMULA
G.f.: x*(1 - 5*x + 8*x^2 - 4*x^3 + x^4) / ((1 - x)*(1 - 3*x + x^2)^2). [restored by Michael D. Weiner, Jul 05 2018]
a(n) = 7*a(n-1) - 17*a(n-2) + 17*a(n-3) - 7*a(n-4) + a(n-5) for n>5. - Colin Barker, Oct 19 2017
a(n) = 1 + Fibonacci(2*n)/5 + Lucas(2*n - 3)*n/5. - Vaclav Kotesovec, Aug 04 2018
MATHEMATICA
Rest[CoefficientList[Series[x*(1 - 5*x + 8*x^2 - 4*x^3 + x^4) / ((1 - x)*(1 - 3*x + x^2)^2), {x, 0, 30}], x]] (* Vaclav Kotesovec, Aug 04 2018 *)
RecurrenceTable[{a[1] == 1, a[2] == 2, a[3] == 5, a[4] == 14, a[5] == 41, a[n] == 7*a[n-1] - 17*a[n-2] + 17*a[n-3] - 7*a[n-4] + a[n-5]}, a, {n, 1, 30}] (* Vaclav Kotesovec, Aug 04 2018 *)
Table[1 + Fibonacci[2*n]/5 + LucasL[2*n - 3]*n/5, {n, 1, 30}] (* Vaclav Kotesovec, Aug 04 2018 *)
PROG
(PARI) Vec(x*(1 - 5*x + 8*x^2 - 4*x^3 + x^4) / ((1 - x)*(1 - 3*x + x^2)^2) + O(x^40)) \\ Colin Barker, Oct 19 2017
CROSSREFS
Cf. A059502 (first differences).
Sequence in context: A370800 A122055 A244885 * A307466 A116849 A371427
KEYWORD
nonn,easy
AUTHOR
Lara Pudwell, Feb 26 2006
STATUS
approved