OFFSET
1,4
LINKS
Seiichi Manyama, Table of n, a(n) for n = 1..18
FORMULA
a(1)=a(2)=a(3)=1; a(n)=(a(n-1)^2+a(n-2)^2+1)/a(n-3).
a(n) ~ 1/4 * c^(((1+sqrt(5))/2)^n), where c = 1.41452525081158447693692520473959... . - Vaclav Kotesovec, Aug 26 2016
a(n)*a(n+1)*a(n+2) = (a(n)^2+a(n+1)^2+a(n+2)^2+1)/4. - Seiichi Manyama, Sep 04 2016
MATHEMATICA
RecurrenceTable[{a[n] == 4*a[n - 1]*a[n - 2] - a[n - 3], a[1] == 1,
a[2] == 1, a[3] == 1}, a, {n, 1, 10}] (* G. C. Greubel, Aug 25 2016 *)
PROG
(Ruby)
def A(m, n)
a = Array.new(m, 1)
ary = [1]
while ary.size < n
a = *a[1..-1], *a[1..-1].inject(:*) * (m + 1) - a[0]
ary << a[0]
end
ary
end
def A276258(n)
A(3, n)
end
CROSSREFS
KEYWORD
nonn
AUTHOR
Seiichi Manyama, Aug 25 2016
STATUS
approved