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A368915 a(n) = 1 if there is no prime p such that p^p divides the arithmetic derivative of n, and 0 otherwise. 9
0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 0, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1 (list; graph; refs; listen; history; text; internal format)
OFFSET
1
COMMENTS
Question: What is the asymptotic mean of this sequence (and its complement A341996)? Knowing the value for A360111 would solve this. See also related sequences like A354874 and A368916.
LINKS
FORMULA
a(1) = 0; for n > 1, a(n) = A359550(A003415(n)).
For all n > 1, a(n) = 1 - A341996(n) = A359550(n) - A360111(n).
For all n > 1, A359550(n) >= a(n) >= A328308(n).
For all n >= 1, a(n) >= A354874(n).
a(n) = A368914(n) - A368913(n).
PROG
(PARI)
A003415(n) = if(n<=1, 0, my(f=factor(n)); n*sum(i=1, #f~, f[i, 2]/f[i, 1]));
A359550(n) = { my(f = factor(n)); prod(k=1, #f~, (f[k, 2]<f[k, 1])); };
A368915(n) = ((n>1)&&A359550(A003415(n)));
CROSSREFS
Characteristic function of A358215.
Cf. A003415, A328308, A341996 (one's complement), A354874, A359550, A360111, A368913, A368914, A368916 [= a(A276086(n))].
Sequence in context: A284929 A286746 A155897 * A144610 A188068 A181632
KEYWORD
nonn
AUTHOR
Antti Karttunen, Jan 09 2024
STATUS
approved

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Last modified August 18 13:06 EDT 2024. Contains 375269 sequences. (Running on oeis4.)