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Revision History for A000149
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FORMULA
a(n)^(1/n) converges to e because |1-a(n)/e^n|=|e^n-a(n)|/e^n < e^(-n) and so a(n)^(1/n)=(e^n*(1+o(1)))^(1/n)=e*(1+o(1)). - Hieronymus Fischer, Jan 22 2006
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LINKS
G. Whyman, N. Ohtori, E. Shulzinger, and Ed. Bormashenko, <a href="https://doi.org/10.1016/j.physa.2016.06.054">Revisiting the Benford law: When the Benford-like distribution of leading digits in sets of numerical data is expectable?</a>, Physica A: Statistical Mechanics and its Applications, 461 (2016), 595-601.
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PROG
(Python)
from sympy import floor, E
def a(n): return floor(E**n)
print([a(n) for n in range(29)]) # Michael S. Branicky, Jul 20 2021
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