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Revision History for A001154

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Showing entries 1-10 | older changes

A001154

Describe the previous term! (method A - initial term is 9).
(history; published version)

#26 by N. J. A. Sloane at Sun Apr 14 10:27:11 EDT 2019

STATUS

editing

approved

#25 by N. J. A. Sloane at Sun Apr 14 10:27:10 EDT 2019

LINKS

S. R. Finch, <a href="http://web.archive.org/web/20010207194413 /http://www.mathsoft.com/asolve/constant/cnwy/cnwy.html">Conway's Constant</a> [From the Wayback Machine]

STATUS

approved

editing

#24 by Peter Luschny at Sat Dec 12 08:05:30 EST 2015

STATUS

reviewed

approved

#23 by Michel Marcus at Fri Dec 11 09:09:20 EST 2015

STATUS

proposed

reviewed

Discussion

Fri Dec 11

11:31

Michel Marcus: and valuation( x, 10) give 1,2,3,3,4,5,5,5,5,5,5,5,5,5,5,5,5,5,5

13:17

Altug Alkan: Best regards.

#22 by Altug Alkan at Sun Dec 06 12:32:08 EST 2015

STATUS

editing

proposed

Discussion

Fri Dec 11

09:08

Michel Marcus: [10, 1100, 2000, 129000, 1112990000, 310198100000, 12900010100000, 1113122099909791900000, 31130009089198002000100000, 132082082098921801009009900000]

#21 by Altug Alkan at Sun Dec 06 12:31:46 EST 2015

COMMENTS

a(n+1) - a(n) is divisible by 10^5 for n > 5. - Altug Alkan, Dec 04 2015

Discussion

Sun Dec 06

12:32

Altug Alkan: I am sorry Mr. Joerg but no. In this sequence last five digits are special for n >5. Please look this example: 132119-3119 is a(5)-a(4) is not divisible by 10^4. Thanks.

#20 by Altug Alkan at Sun Dec 06 12:31:26 EST 2015

COMMENTS

a(n+1) - a(n) is divisible by 10^5 for n > 5. - Altug Alkan, Dec 04 2015

STATUS

proposed

editing

#19 by Jon E. Schoenfield at Sat Dec 05 19:51:18 EST 2015

STATUS

editing

proposed

Discussion

Sun Dec 06

11:16

Joerg Arndt: Isn't more true, such as "a(n+1)-a(n) is divisible by 10^n." ?

#18 by Jon E. Schoenfield at Sat Dec 05 19:51:16 EST 2015

AUTHOR

N. J. A. Sloane.

STATUS

proposed

editing

#17 by Michel Marcus at Fri Dec 04 11:23:04 EST 2015

STATUS

editing

proposed