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Sum_{n>=1} 1/a(n) = A367110 = 1.428591545852638123996854844400537952781688750906133068397189529775365950039... (calculated using Baillie's irwinSums.m, see Links). - Amiram Eldar, Feb 14 2022
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A000120(a(n)) = 3. [_- _Reinhard Zumkeller_, May 03 2012]
Sum_{n>=1} 1/a(n) = 1.428591545852638123996854844400537952781688750906133068397189529775365950039744428591545852638123996854844400537952781688750906133068397189529775365950039... (calculated using Baillie's irwinSums.m, see Links). - Amiram Eldar, Feb 14 2022
Robert Baillie, <a href="http://arxiv.org/abs/0806.4410">Summing the curious series of Kempner and Irwin</a>, arXiv:0806.4410 [math.CA], 2008-2015. See p. 18 for Mathematica code irwinSums.m.
Sum_{n>=1} 1/a(n) = 1.428591545852638123996854844400537952781688750906133068397189529775365950039744
approved
editing
reviewed
approved
proposed
reviewed