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Revision History for A077025

(Underlined text is an addition; strikethrough text is a deletion.)

Showing all changes.
A077025 a(n) = Sum_{k=1..n} floor(n/(k + 1/2)).
(history; published version)
#9 by Andrey Zabolotskiy at Wed Jan 03 06:31:52 EST 2024
STATUS

editing

approved

#8 by Andrey Zabolotskiy at Wed Jan 03 06:31:50 EST 2024
NAME

a(n) = Sum_{k=1..n} floor(n/(k + 1/2))}.)).

STATUS

approved

editing

#7 by Michael De Vlieger at Sat Jan 14 09:42:14 EST 2023
STATUS

reviewed

approved

#6 by Joerg Arndt at Sat Jan 14 09:27:00 EST 2023
STATUS

proposed

reviewed

#5 by Michel Marcus at Sat Jan 14 09:21:26 EST 2023
STATUS

editing

proposed

#4 by Michel Marcus at Sat Jan 14 09:21:20 EST 2023
NAME

a(n) = Sum{Floor_{k=1..n} floor(n/(k + 1/2)): k=1,2,...,n}.))}.

PROG

(PARI) a(n) = sum(k=1, n, n\(k+1/2)); \\ Michel Marcus, Jan 14 2023

STATUS

approved

editing

#3 by Russ Cox at Fri Mar 30 18:57:04 EDT 2012
AUTHOR

_Clark Kimberling (ck6(AT)evansville.edu), _, Oct 18 2002

Discussion
Fri Mar 30 18:57 
OEIS Server: https://oeis.org/edit/global/285
#2 by N. J. A. Sloane at Sun Feb 20 03:00:00 EST 2005
NAME

SUMSum{Floor(n/(k + 1/2)): k=1,2,...,n}.

KEYWORD

nonn,new

nonn

#1 by N. J. A. Sloane at Fri May 16 03:00:00 EDT 2003
NAME

SUM{Floor(n/(k + 1/2)): k=1,2,...,n}.

DATA

0, 1, 3, 4, 7, 9, 11, 14, 17, 19, 23, 25, 28, 32, 36, 37, 41, 46, 48, 52, 56, 58, 64, 66, 70, 74, 78, 82, 86, 90, 92, 97, 103, 105, 111, 114, 116, 122, 128, 130, 135, 139, 143, 147, 153, 157, 161, 165, 168, 175, 179, 181, 189, 193, 197, 201, 205, 209, 215, 221, 224

OFFSET

1,3

COMMENTS

It appears that A077024(n) - a(n) = n.

EXAMPLE

[4/(1 + 1/2)] + [4/(2 + 1/2)] + [4/(3 + 1/2)] + [4/(4 + 1/2)] = 2+1+1+0 = 4 = a(4).

CROSSREFS

Cf. A077024.

KEYWORD

nonn

AUTHOR

Clark Kimberling (ck6(AT)evansville.edu), Oct 18 2002

STATUS

approved

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Last modified August 18 19:26 EDT 2024. Contains 375273 sequences. (Running on oeis4.)