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Revision History for A080423

(Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
a(n) = (n+1)*(n+2)*(n+3)*(n+4)*(n+15)*3^n/360.
(history; published version)
#25 by Joerg Arndt at Thu Jan 11 01:39:28 EST 2024
STATUS

reviewed

approved

#24 by Michel Marcus at Thu Jan 11 01:32:25 EST 2024
STATUS

proposed

reviewed

#23 by Amiram Eldar at Thu Jan 11 01:23:25 EST 2024
STATUS

editing

proposed

#22 by Amiram Eldar at Thu Jan 11 00:51:38 EST 2024
DATA

1, 16, 153, 1134, 7182, 40824, 214326, 1058508, 4979799, 22517352, 98513415, 419129802, 1741000716, 7083045648, 28296044604, 111232727064, 431026817373, 1648861601184, 6234757929477, 23328137324646, 86451332438394, 317576323243080, 1157228874847890, 4185605730648420

#21 by Amiram Eldar at Thu Jan 11 00:50:38 EST 2024
FORMULA

From Amiram Eldar, Jan 11 2024: (Start)

Sum_{n>=0} 1/a(n) = 215084880*log(3/2)/1001 - 99766344351/1145144.

Sum_{n>=0} (-1)^n/a(n) = 216218880*log(4/3)/1001 - 498108421095/8016008. (End)

STATUS

approved

editing

#20 by Michael De Vlieger at Sat Dec 23 11:11:56 EST 2023
STATUS

reviewed

approved

#19 by Stefano Spezia at Sat Dec 23 02:25:02 EST 2023
STATUS

proposed

reviewed

#18 by Stefano Spezia at Fri Dec 22 02:48:47 EST 2023
STATUS

editing

proposed

#17 by Stefano Spezia at Fri Dec 22 02:43:31 EST 2023
FORMULA

G.f. : (1-2*x)/(1-3*x)^6.

PROG

(Magma) [Floor((n+1)*(n+2)*(n+3)*(n+4)*(n+15)*3^n/360): n in [0..30]]; // Vincenzo Librandi, Aug 05 2013

STATUS

proposed

editing

#16 by G. C. Greubel at Fri Dec 22 02:41:34 EST 2023
STATUS

editing

proposed