STATUS
reviewed
approved
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Revision History for A084984
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STATUS
proposed
reviewed
STATUS
editing
proposed
FORMULA
a(n) <= 4*10^(log_6(n-1)-log_6(2)) = 1.641372618*10^(log_6(n-1) , ), equality holds for n=2*6^k+1, k>=0.
a(n) > 2*10^(log_6(n-1)-log_6(2)) = 0.820686309*10^(log_6(n-1)).
STATUS
approved
editing
STATUS
reviewed
approved
STATUS
proposed
reviewed
STATUS
editing
proposed
COMMENTS
Complement of A118950. - Reinhard Zumkeller, Jul 19 2011
FORMULA
A193238(a(n)) = 0; complement of A118950. - Reinhard Zumkeller, Jul 19 2011
COMMENTS
A193238(a(n)) = 0; complement of A118950. - Reinhard Zumkeller, Jul 19 2011
FORMULA
A193238(a(n)) = 0; complement of A118950. - Reinhard Zumkeller, Jul 19 2011