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P:=proc(q, h) local a, b, c, k, n, x; x:=[h]; for n from 1 to q do
a:=convert(x[n], base, 10); b:=0; for k from 0 to 9 do c:=numboccur(a, k);
if c>0 then b:=b*10^(ilog10(c*10+k)+1)+c*10+k; fi; od; x:=[op(x), b];
od; print(op(x)); end: P(25, 3); # Paolo P. Lava, Aug 30 2018
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a(n) = 21322314 for n > 12; a(n) = A005151(n) for n > 6. - Reinhard Zumkeller, Jan 26 2014
a(n) = 21322314 for n > 12; a(n) = A005151(n) for n > 6. - Reinhard Zumkeller, Jan 26 2014
3, 13, 1113, 3113, 2123, 112213, 312213, 212223, 114213, 31121314, 41122314, 31221324, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314, 21322314
a(n) = A047842(a(n-1)). - Pontus von Brömssen, Jun 04 2023
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P:=proc(q, h) local a, b, c, k, n, x; x:=[h]; for n from 1 to q do
a:=convert(x[n], base, 10); b:=0; for k from 0 to 9 do c:=numboccur(a, k);
if c>0 then b:=b*10^(ilog10(c*10+k)+1)+c*10+k; fi; od; x:=[op(x), b];
od; print(op(x)); end: P(25, 3); # Paolo P. Lava, Aug 30 2018
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