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Revision History for A121706
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n^3 divides a(n) for n = {35, 55, 77, 95, 115, 119, 143, 155, 161,...} = in A121707.
p divides a((p+1)/2) for prime p = {7, 11, 19, 23, 31, 43, 47, 59, 67, 71,...} = primes in A002145: primes of the form 4n+3, n >= 1.
p^2 divides a((p+1)/2) for prime p = {7, 23, 31, 47, 71, 79, 103, 127,...} = primes in A007522: primes of the form 8n+7, n >= 0.
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LINKS
Seiichi Manyama, <a href="/A121706/b121706.txt">Table of n, a(n) for n = 1..386</a>
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n*(2n2*n+1) divides a(2n2*n+1) for n >= 1. - Franz Vrabec, Dec 20 2020
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n*(2n+1) divides a(2n+1) for n >= 1. _- _Franz Vrabec_, Dec 20 2020
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