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Revision History for A130062

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Showing entries 1-10 | older changes
Nonprime numbers k such that k divides 3^((k+1)/2) - 2^((k+1)/2) - 1.
(history; published version)
#15 by Joerg Arndt at Sat Sep 21 03:50:08 EDT 2024
STATUS

reviewed

approved

#14 by Michel Marcus at Sat Sep 21 03:03:17 EDT 2024
STATUS

proposed

reviewed

#13 by Jason Yuen at Sat Sep 21 03:02:34 EDT 2024
STATUS

editing

proposed

#12 by Jason Yuen at Sat Sep 21 03:02:23 EDT 2024
CROSSREFS

Cf. A097934 (primes p that divide 3^((p-1)/2) - 2^((p-1)/2)).

Cf. A038876 (primes p such that 6 is a square mod p).

STATUS

approved

editing

#11 by Susanna Cuyler at Fri Mar 26 08:39:11 EDT 2021
STATUS

proposed

approved

#10 by Michel Marcus at Fri Mar 26 05:24:39 EDT 2021
STATUS

editing

proposed

#9 by Michel Marcus at Fri Mar 26 05:24:34 EDT 2021
COMMENTS

The perfect squares in listed terms are a(1) = 1, a(3) = 49 = 7^2, a(13) = 32041 = 179^2 and a(29) = 383161 = 619^2. Note that primes {7,179,619} are the terms of A130060(n) = {2,3,7,179,619,17807,...} = Primes p such that p^2 divides 3^p - 2^p - 1; or primes in A127074(n).

Note that primes {7,179,619} are the terms of A130060 or primes in A127074.

CROSSREFS

Cf. A097934 = Primes p such that p divides 3^((p-1)/2) - 2^((p-1)/2). Cf. A038876(n) = Primes p such that 6 is a square mod p. Cf. A127071, A127072, A127073, A127074. Cf. A130058, A130059, A130061, A130063, A130060 = Primes p such that p^2 divides 3^p - 2^p - 1; or primes in A127074(n).

Cf. A097934 (primes p that divide 3^((p-1)/2) - 2^((p-1)/2).

Cf. A038876 (primes p such that 6 is a square mod p.

Cf. A127071, A127072, A127073, A127074.

Cf. A130058, A130059, A130061, A130063, A130060, A127074.

STATUS

proposed

editing

#8 by Amiram Eldar at Fri Mar 26 04:59:40 EDT 2021
STATUS

editing

proposed

#7 by Amiram Eldar at Fri Mar 26 04:44:25 EDT 2021
NAME

Nonprime n numbers k such that n k divides 3^((nk+1)/2) - 2^((nk+1)/2) - 1.

#6 by Amiram Eldar at Fri Mar 26 04:43:47 EDT 2021
LINKS

Amiram Eldar, <a href="/A130062/b130062.txt">Table of n, a(n) for n = 1..1000</a>

STATUS

approved

editing