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#16 by Peter Luschny at Tue Aug 10 11:11:56 EDT 2021
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#15 by Joerg Arndt at Tue Aug 10 09:07:50 EDT 2021
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#14 by Jinyuan Wang at Tue Aug 10 08:24:24 EDT 2021
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#13 by Jinyuan Wang at Tue Aug 10 08:24:19 EDT 2021
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| EXAMPLE
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Row 20 is ( {2, -2, 1). }. So 20 = prime(1)^T(20,1) * prime(2)^(T(20,1) + T(20,2)) * prime(3)^(T(20,1) + T(20,2) + T(20,3)) = 2^2 * 3^(2 - 2) * 5^(2 - 2 + 1) = 2^2 * 3^0 * 5^1.
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#12 by Jinyuan Wang at Tue Aug 10 08:23:41 EDT 2021
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| EXAMPLE
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Triangle begins:
0;
1;
0, 1;
2;
0, 0, 1;
1, 0;
0, 0, 0, 1;
3;
...
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#11 by Jinyuan Wang at Tue Aug 10 08:21:01 EDT 2021
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| NAME
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Irregular triangle read by arrayrows where n-th row (of A061395(n) terms, for n>=2) is such that n = product{kProduct_{j=1 to ..A061395(n)} pprime(k)^(sum{j)^(Sum_{k=1 to k} a(n,..j)) (where a} T(n,j) is the j-th term of the n-th row of the array and p(k) is the k-th prime). )). Row 1 is {0}.
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| COMMENTS
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The rows of this arraytriangle also give all the ordered ways that a finite number of integers can be arranged so that their partial sums, from left to right, are all nonnegative and their total sum is positive.
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| EXAMPLE
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Row 20 is (2,-, -2,, 1). So 20 is p = prime(1)^aT(20,1) * pprime(2)*(a)^(T(20,1)+a) + T(20,2)) * pprime(3)^(aT(20,1)+a) + T(20,2)+a) + T(20,3)) = 2^2 * 3^(2- - 2) * 5^(2- - 2+ + 1) = 2^2 * * 3^0 * * 5^1.
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| KEYWORD
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tabf,sign
sign,tabf
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| STATUS
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approved
editing
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#10 by Charles R Greathouse IV at Tue Mar 11 01:32:23 EDT 2014
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| AUTHOR
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___Leroy Quet__, _, Oct 22 2007
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Discussion
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| Tue Mar 11
| 01:32
| OEIS Server: https://oeis.org/edit/global/2122
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#9 by N. J. A. Sloane at Wed Feb 05 20:18:43 EST 2014
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| AUTHOR
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___Leroy Quet_, __, Oct 22 2007
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Discussion
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| Wed Feb 05
| 20:18
| OEIS Server: https://oeis.org/edit/global/2118
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#8 by N. J. A. Sloane at Wed Feb 05 20:11:58 EST 2014
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| AUTHOR
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_Leroy Quet, _, Oct 22 2007
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Discussion
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| Wed Feb 05
| 20:11
| OEIS Server: https://oeis.org/edit/global/2117
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#7 by Bruno Berselli at Fri Apr 12 01:41:17 EDT 2013
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