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#42 by N. J. A. Sloane at Fri Feb 10 12:54:52 EST 2023
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#41 by Vaclav Kotesovec at Fri Feb 10 12:34:48 EST 2023
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#40 by Vaclav Kotesovec at Fri Feb 10 12:34:13 EST 2023
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Dirichlet g.f.: 1 / Product_{p prime} (1 - p^(1 - s) + 2p^2*p^(-s). )). The Dirichlet inverse is multiplicative with b(p) = 2 - p, b(p^e) = 0, for e > 1. - Álvar Ibeas, Nov 24 2017 [corrected by _Vaclav Kotesovec_, Feb 10 2023]
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approved
editing
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#39 by Vaclav Kotesovec at Fri Feb 10 12:33:18 EST 2023
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#38 by Vaclav Kotesovec at Fri Feb 10 12:33:10 EST 2023
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Sum_{k=1..n} a(k) ~ c * n^2/2, where c = Product_{primes} (1 - 1/(1 + p*(p-1)/2)) = 0.3049173579282080265466051390930446635010608835584906520231313997... - Vaclav Kotesovec, Feb 10 2023
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approved
editing
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#37 by Vaclav Kotesovec at Fri Feb 10 12:03:09 EST 2023
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#36 by Vaclav Kotesovec at Fri Feb 10 12:02:49 EST 2023
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(PARI) for(n=1, 100, print1(direuler(p=2, n, 1/(1-p*X+2*X))[n], ", ")) \\ Vaclav Kotesovec, Feb 10 2023
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approved
editing
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#35 by Bruno Berselli at Tue Nov 28 11:54:10 EST 2017
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#34 by Joerg Arndt at Tue Nov 28 11:39:39 EST 2017
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#33 by Álvar Ibeas at Fri Nov 24 13:31:31 EST 2017
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