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Revision History for A220420

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Showing entries 1-10 | older changes
Express the Sum_{n>=0} p(n)*x^n, where p(n) is the partition function, as a product Product_{k>=1} (1 + a(k)*x^k).
(history; published version)
#54 by Michel Marcus at Mon Oct 07 02:42:31 EDT 2019
STATUS

reviewed

approved

#53 by Joerg Arndt at Mon Oct 07 01:56:11 EDT 2019
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proposed

reviewed

#52 by Petros Hadjicostas at Mon Oct 07 01:36:02 EDT 2019
STATUS

editing

proposed

#51 by Petros Hadjicostas at Mon Oct 07 01:35:51 EDT 2019
COMMENTS

Alkauskas (2016, Problem 3, p. 3) conjectured that a(8*k+2), a(8*k+4), and a(8*k+6) are all negative , and a(8*k) is positive for k >= 1. [This statement is not wholly true for k = 0.] - Petros Hadjicostas, Oct 07 2019

#50 by Petros Hadjicostas at Mon Oct 07 01:35:20 EDT 2019
COMMENTS

Alkauskas (2016, Problem 3, p. 3) conjectured that a(8*k+2), a(8*k+4), and a(8*k+6) are all negative and a(8*k) is positive for k >= 1. [This statement is not wholly true for k = 0.] - Petros Hadjicostas, Oct 07 2019

STATUS

approved

editing

#49 by N. J. A. Sloane at Fri Oct 04 07:54:18 EDT 2019
STATUS

proposed

approved

#48 by Petros Hadjicostas at Fri Oct 04 06:36:39 EDT 2019
STATUS

editing

proposed

#47 by Petros Hadjicostas at Fri Oct 04 06:36:36 EDT 2019
LINKS

W. Lang, <a href="/A157162/a157162.txt">Recurrences for the general problem</a>.

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proposed

editing

#46 by Petros Hadjicostas at Fri Oct 04 04:29:05 EDT 2019
STATUS

editing

proposed

#45 by Petros Hadjicostas at Fri Oct 04 04:29:03 EDT 2019
FORMULA

Define (A(m,n): n,m >= 1) by A(m=1,n) = p(n) = A000041(n) for n >= 1, A(m,n) = 0 for m > n >= 1 (upper triangular), and A(m,n) = A(m-1,n) - A(m-1,m-1) * A(m,n-m+1) for n >= m >= 12. Then a(n) = A(n,n). [Theorem 3 in Gingold et al. (1988).]

STATUS

proposed

editing