reviewed
approved
reviewed
approved
proposed
reviewed
editing
proposed
Alkauskas (2016, Problem 3, p. 3) conjectured that a(8*k+2), a(8*k+4), and a(8*k+6) are all negative , and a(8*k) is positive for k >= 1. [This statement is not wholly true for k = 0.] - Petros Hadjicostas, Oct 07 2019
Alkauskas (2016, Problem 3, p. 3) conjectured that a(8*k+2), a(8*k+4), and a(8*k+6) are all negative and a(8*k) is positive for k >= 1. [This statement is not wholly true for k = 0.] - Petros Hadjicostas, Oct 07 2019
approved
editing
proposed
approved
editing
proposed
W. Lang, <a href="/A157162/a157162.txt">Recurrences for the general problem</a>.
proposed
editing
editing
proposed
Define (A(m,n): n,m >= 1) by A(m=1,n) = p(n) = A000041(n) for n >= 1, A(m,n) = 0 for m > n >= 1 (upper triangular), and A(m,n) = A(m-1,n) - A(m-1,m-1) * A(m,n-m+1) for n >= m >= 12. Then a(n) = A(n,n). [Theorem 3 in Gingold et al. (1988).]
proposed
editing