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Revision History for A230000

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Showing all changes.
Triangular array read by rows: row n shows the coefficients of the polynomial u(n) = c(0) + c(1)*x + ... + c(k)*x^k which is the numerator of the n-th convergent of the continued fraction [1, 1/x, 1/x^2, ... ,1/x^n].
(history; published version)
#7 by Bruno Berselli at Tue Aug 05 09:17:22 EDT 2014
STATUS

editing

approved

#6 by Bruno Berselli at Tue Aug 05 09:17:17 EDT 2014
NAME

Triangular array read by rows: row n shows the coefficients of the polynomial u(n) = c(0) + c(1)*x + ... + c(k)*x^k which is the numerator of the nth n-th convergent of the continued fraction [1, 1/x, 1/x^2, ... ,1/x^n].

STATUS

approved

editing

#5 by N. J. A. Sloane at Sun Oct 13 18:00:59 EDT 2013
STATUS

editing

approved

#4 by N. J. A. Sloane at Sun Oct 13 18:00:56 EDT 2013
NAME

ArrayTriangular array read by rows: row n shows the coefficients of the polynomial u(n) = c(0) + c(1)*x + ... + c(k)*x^k which is the numerator of the nth convergent of the continued fraction [1, 1/x, 1/x^2, ... ,1/x^n].

STATUS

proposed

editing

#3 by Clark Kimberling at Fri Oct 11 21:41:09 EDT 2013
STATUS

editing

proposed

#2 by Clark Kimberling at Fri Oct 11 21:38:06 EDT 2013
NAME

allocated for Clark KimberlingArray: row n shows the coefficients of the polynomial u(n) = c(0) + c(1)*x + ... + c(k)*x^k which is the numerator of the nth convergent of the continued fraction [1, 1/x, 1/x^2, ... ,1/x^n].

DATA

1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 2, 0, 1, 0, 1, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 2, 1, 2, 0, 2, 1, 1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 2, 1, 2, 1

OFFSET

0,36

COMMENTS

In the Name section, k = n(n+1)/2. For the denominator polynomials, see A230001. Conjecture: every nonnegative integer occurs infinitely many times.

FORMULA

Write the numerator polynomials as u(0), u(1), u(2), ... and the denominator polynomials as v(0), v(1), v(2),... Let p(0) = 1, q(0) = 1; p(1) = (1 + x)/x; q(1) = 1/x; p(n ) = p(n-1)/x^n + p(n-2), q(n) = q(n-1)/x^n + q(n-2). Then u(n)/v(n) = p(n)/q(n) for n>=0.

EXAMPLE

The first 7 rows:

1 . . . . . . . . . . . . polynomial u(0) = 1

1 1 . . . . . . . . . . . polynomial u(1) = 1 + x

1 1 0 1 . . . . . . . . . u(2) = 1 + x + x^3

1 1 0 1 0 1 1

1 1 0 1 0 1 1 1 1 0 1

1 1 0 1 0 1 1 1 1 1 2 0 1 0 1 1

1 1 0 1 0 1 1 1 1 1 2 1 2 0 2 1 1 1 1 1 0 1

MATHEMATICA

t[n_] := t[n] = Table[1/x^k, {k, 0, n}];

b = Table[Factor[Convergents[t[n]]], {n, 0, 10}];

p[x_, n_] := p[x, n] = Last[Expand[Numerator[b]]][[n]];

u = Table[p[x, n], {n, 1, 10}]

v = CoefficientList[u, x]

Flatten[v]

CROSSREFS

Cf. A230001.

KEYWORD

allocated

nonn,tabf

AUTHOR

Clark Kimberling, Oct 11 2013

STATUS

approved

editing

#1 by Clark Kimberling at Sat Oct 05 10:58:03 EDT 2013
NAME

allocated for Clark Kimberling

KEYWORD

allocated

STATUS

approved