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Revision History for A234364

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A234364

Primes which are the arithmetic mean of the squares of four consecutive primes.
(history; published version)

#14 by Harvey P. Dale at Wed Oct 08 16:45:35 EDT 2014

STATUS

editing

approved

#13 by Harvey P. Dale at Wed Oct 08 16:45:30 EDT 2014

MATHEMATICA

Select[Mean/@(Partition[Prime[Range[200]], 4, 1]^2), PrimeQ] (* Harvey P. Dale, Oct 08 2014 *)

STATUS

approved

editing

#12 by Bruno Berselli at Fri Dec 27 02:58:41 EST 2013

STATUS

editing

approved

#11 by Bruno Berselli at Fri Dec 27 02:58:15 EST 2013

CROSSREFS

Cf. A084951 (: primes: of the form (prime(pk)^2 + qprime(k+1)^2 + rprime(k+2)^2)/3).

Cf. A093343 (: primes: of the form (prime(nk)^2 + prime(nk+1)^2)/2).

STATUS

proposed

editing

#10 by Alonso del Arte at Thu Dec 26 21:18:50 EST 2013

STATUS

editing

proposed

#9 by Alonso del Arte at Thu Dec 26 21:18:37 EST 2013

CROSSREFS

Cf. A084951 (primes: (p^2 + q^2 + r^2)/3).

Cf. A093343 (primes: (prime(n)^2 + prime(n+1)^2)/2).

#8 by Alonso del Arte at Thu Dec 26 21:16:52 EST 2013

MATHEMATICA

Select[Table[Mean[Prime[Range[n, n + 3]]^2], {n, 250}], PrimeQ] (* Alonso del Arte, Dec 26 2013 *)

STATUS

reviewed

editing

#7 by Michael B. Porter at Thu Dec 26 21:13:08 EST 2013

STATUS

proposed

reviewed

#6 by Michael B. Porter at Thu Dec 26 21:12:55 EST 2013

STATUS

editing

proposed

#5 by Michael B. Porter at Thu Dec 26 21:12:26 EST 2013

EXAMPLE

157 is in the sequence because (7^2 + 11^2 + 13^2 + 17^2)/4 = 157 which is prime.

1213 is in the sequence because (29^2 + 31^2 + 37^2 + 41^2)/4 = 1213 which is prime.

STATUS

proposed

editing