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Revision History for A246659

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Showing entries 1-10 | older changes
a(n) = binomial(n-h,h)*hypergeometric([h-n/2,h-(n-1)/2],[1],4), h = floor(n/4).
(history; published version)
#26 by Michel Marcus at Tue Jun 18 02:11:21 EDT 2024
STATUS

reviewed

approved

#25 by Joerg Arndt at Tue Jun 18 02:05:06 EDT 2024
STATUS

proposed

reviewed

#24 by Jean-François Alcover at Tue Jun 18 01:59:23 EDT 2024
STATUS

editing

proposed

#23 by Jean-François Alcover at Tue Jun 18 01:58:42 EDT 2024
MATHEMATICA

a[n_] := With[{h = Quotient[n, 4]}, Binomial[n-h, h]*Hypergeometric2F1[h-n/2, h-(n-1)/2, 1, 4]];

Table[a[n], {n, 0, 30}] (* Jean-François Alcover, Jun 18 2024 *)

STATUS

approved

editing

#22 by N. J. A. Sloane at Wed Dec 02 12:16:32 EST 2015
STATUS

proposed

approved

#21 by Altug Alkan at Sun Nov 29 17:05:11 EST 2015
STATUS

editing

proposed

#20 by Altug Alkan at Sun Nov 29 17:00:09 EST 2015
COMMENTS

a(n) is the k-th term of n-th row of triangle of A132885 where k = floor(n/4), k >= 0, n >= 0. - Altug Alkan, Nov 29 2015

#19 by Altug Alkan at Sun Nov 29 16:58:47 EST 2015
FORMULA

a(n) = A132885(n, floor(n/4)), that is, a(n) = A132885(A054925(n+2) - 1), n >= 0. - Altug Alkan, Nov 29 2015

STATUS

proposed

editing

#18 by Altug Alkan at Sun Nov 29 15:00:31 EST 2015
STATUS

editing

proposed

#17 by Altug Alkan at Sun Nov 29 14:34:18 EST 2015
COMMENTS

a(n) is the k-th term of n-th row of triangle of A132885 where k = floor(n/4 + 1) -1, , k >= 0, n >= 0. - Altug Alkan, Nov 29 2015

STATUS

proposed

editing