|
|
|
|
#33 by Alois P. Heinz at Fri Mar 15 22:48:58 EDT 2019
|
|
|
|
#32 by Michael B. Porter at Sat Mar 02 03:19:34 EST 2019
|
|
|
Discussion
|
Sun Mar 03
| 14:10
| Georg Fischer: I did not know what "Brazilian numbers" are (neither Wikipedia nor MathWorld has them), and the way to the definition in A125134 might be made a bit more direct in the comment.
|
|
|
|
#31 by Michel Marcus at Thu Feb 28 01:33:18 EST 2019
|
|
|
|
#30 by Michel Marcus at Thu Feb 28 01:32:36 EST 2019
|
| COMMENTS
|
Conjecture: Let r(n) = (a(n) - 1)/(a(n) + 1); then Product_{n>=1} r(n) = (15/17) * (35/37) * (63/65) * (40/41) * (99/101) * (60/61) * (143/145) * (195/197) * ... = (150 * Pi) / (61 * sinh(Pi)) = 0.668923905.... - .... - _Dimitris Valianatos, _, Feb 27 2019
|
| STATUS
|
proposed
editing
|
|
|
Discussion
|
Thu Feb 28
| 01:33
| Michel Marcus: attribution fixed
|
|
|
|
#29 by Dimitris Valianatos at Wed Feb 27 20:04:48 EST 2019
|
|
|
|
#28 by Dimitris Valianatos at Wed Feb 27 20:04:43 EST 2019
|
| COMMENTS
|
Conjecture: Let r(n) = (a(n) - 1)/(a(n) + 1); then Product_{n>=1} r(n) = (15/17) * (35/37) * (63/65) * (40/41) * (99/101) * (60/61) * (143/145) * (195/197) * ... = (150 * Pi) / (61 * sinh(Pi)) = 0.668923905.... - Dimitris Valianatos, Feb 27 2019
|
| STATUS
|
approved
editing
|
|
|
|
#27 by Michel Marcus at Sun Jul 30 14:51:09 EDT 2017
|
|
|
|
#26 by Joerg Arndt at Sun Jul 30 13:28:57 EDT 2017
|
|
|
|
#25 by Jon E. Schoenfield at Sun Jul 30 13:25:36 EDT 2017
|
|
|
|
#24 by Jon E. Schoenfield at Sun Jul 30 13:25:32 EDT 2017
|
| EXAMPLE
|
a(1) = 16 = 4^2 = (22)_7. a(6) = 121 = 11^2 = (11111)_3. - Bernard Schott, May 01 2017
From Bernard Schott, May 01 2017: (Start)
a(1) = 16 = 4^2 = 22_7.
a(6) = 121 = 11^2 = 11111_3. (End)
|
| STATUS
|
approved
editing
|
|
|
|