STATUS
proposed
approved
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Revision History for A295514
(Bold, blue-underlined text is an addition; faded, red-underlined text is aShowing entries 1-10 | older changes
a(n) = 2^bil(n) - bil(n) where bil(0) = 0 and bil(n) = floor(log_2(n)) + 1 for n > 0.
(history; published version)
(history; published version)
STATUS
editing
proposed
NAME
a(n) = 2^bil(n) - bil(n) where bil(0) = 0 and bil(n) = floor(log_2(n)) + 1 for n > 0.
FORMULA
a(n) = 4*a(floor(n/2)) - 5*a(floor(n/4)) + 2*a(floor(n/8)) for n >= 4. (End)
STATUS
proposed
editing
STATUS
editing
proposed
LINKS
Robert Israel, <a href="/A295514/b295514.txt">Table of n, a(n) for n = 0..10000</a>
FORMULA
From Robert Israel, Dec 03 2017: (Start)
G.f. (1-x)^(-1)*(1+Sum_{k>=0} (2^k-1)*x^(2^k)). - _Robert Israel_, Dec 03 2017
a(n)=4*a(floor(n/2))-5*a(floor(n/4))+2*a(floor(n/8)) for n >= 4. (End)
FORMULA
G.f. (1-x)^(-1)*(1+Sum_{k>=0} (2^k-1)*x^(2^k)). - Robert Israel, Dec 03 2017
MAPLE
1, seq((2^k-k)$(2^(k-1)), k=1..8); # Robert Israel, Dec 03 2017
STATUS
approved
editing
STATUS
reviewed
approved
STATUS
proposed
reviewed
STATUS
editing
proposed
CROSSREFS
Cf. A000325.
STATUS
proposed
editing