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Revision History for A303558

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Showing entries 1-10 | older changes
G.f. A(x) satisfies: 0 = [x^(n-1)] (x*A(x))' / (1 + x*A(x)^n)^n for n>1.
(history; published version)
#15 by Paul D. Hanna at Fri Apr 27 12:38:53 EDT 2018
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approved

#14 by Paul D. Hanna at Fri Apr 27 12:38:51 EDT 2018
EXAMPLE

in which the main diagonal is all zeros after the initial term, illustrating the identity: 0 = [x^(n-1)] (x*A(x))' / A(x)^n for n>1 holds since FA(0) = 1.

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#13 by Paul D. Hanna at Fri Apr 27 12:38:34 EDT 2018
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approved

#12 by Paul D. Hanna at Fri Apr 27 12:38:33 EDT 2018
COMMENTS

Related identity: 0 = [x^(n-1)] (x*F(x))' / F(x)^n for n>1 holds when F(0) = 1.

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editing

#11 by Paul D. Hanna at Fri Apr 27 12:17:29 EDT 2018
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approved

#10 by Paul D. Hanna at Fri Apr 27 12:17:27 EDT 2018
EXAMPLE

RELATED TABLE.

The table of coefficients of x^k in (x*A(x))' / A(x)^n begins:

n=1: [1, 1, 5, 37, 305, 2516, 19205, 126624, 792081, 10741078, ...];

n=2: [1, 0, 2, 20, 186, 1620, 12495, 79302, 474495, 7998088, ...];

n=3: [1, -1, 0, 8, 100, 969, 7680, 46440, 261588, 5988094, ...];

n=4: [1, -2, -1, 0, 40, 510, 4337, 24608, 126090, 4504280, ...];

n=5: [1, -3, -1, -5, 0, 199, 2120, 11037, 46376, 3386810, ...];

n=6: [1, -4, 0, -8, -25, 0, 749, 3514, 5499, 2514128, ...];

n=7: [1, -5, 2, -10, -39, -116, 0, 290, -9640, 1795607, ...];

n=8: [1, -6, 5, -12, -45, -172, -304, 0, -9000, 1165374, ...];

n=9: [1, -7, 9, -15, -45, -186, -301, 1594, 0, 577155, ...];

n=10: [1, -8, 14, -20, -40, -172, -97, 4278, 11976, 0, ...]; ...

in which the main diagonal is all zeros after the initial term, illustrating the identity: 0 = [x^(n-1)] (x*A(x))' / A(x)^n for n>1 holds since F(0) = 1.

CROSSREFS

Cf. A303559.

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approved

editing

#9 by Paul D. Hanna at Thu Apr 26 22:54:04 EDT 2018
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approved

#8 by Paul D. Hanna at Thu Apr 26 22:54:03 EDT 2018
COMMENTS

Compare to: 0 = [x^(n-1)] (x*G(x))' / (1 + x*G(x)^k)^n for n>1 holds when G(x) = 1 + x*G(x)^k and k is fixed; the g.f. of this sequence explores the case where k varies directly with n.

STATUS

approved

editing

#7 by Paul D. Hanna at Thu Apr 26 18:20:33 EDT 2018
STATUS

editing

approved

#6 by Paul D. Hanna at Thu Apr 26 18:20:31 EDT 2018
COMMENTS

Compare to: 0 = [x^(n-1)] (x*G(x))' / (1 + x*G(x)^k)^n for n>1 holds when G(x) = 1 + x*G(x)^k and k is fixed; the g.f. of this sequence describes explores the case where k varies directly with n.

STATUS

approved

editing