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Revision History for A308813

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Showing entries 1-10 | older changes
Square array A(n,k), n >= 1, k >= 0, read by descending antidiagonals, where A(n,k) is Sum_{d|n} k^(d-1).
(history; published version)
#41 by Peter Luschny at Fri Jun 28 05:05:06 EDT 2024
STATUS

reviewed

approved

#40 by Joerg Arndt at Fri Jun 28 02:27:20 EDT 2024
STATUS

proposed

reviewed

#39 by Michel Marcus at Thu Jun 27 00:33:33 EDT 2024
STATUS

editing

proposed

#38 by Michel Marcus at Thu Jun 27 00:33:29 EDT 2024
NAME

Square array A(n,k), n >= 1, k >= 0, read by descending antidiagonals, where A(n,k) is Sum_{d|n} k^(d-1).

STATUS

proposed

editing

#37 by G. C. Greubel at Wed Jun 26 19:52:18 EDT 2024
STATUS

editing

proposed

#36 by G. C. Greubel at Wed Jun 26 19:50:31 EDT 2024
FORMULA

T(n, k) = Sum_{d|(k+1)} (n-k-1)^(d-1), with T(n, n) = 1. - G. C. Greubel, Jun 26 2024

EXAMPLE

Square array , A(n,k), begins:

Antidiagonal triangle, T(n,k), begins as:

1;

1, 1;

1, 2, 1;

1, 3, 2, 1;

1, 4, 5, 3, 1;

1, 5, 10, 11, 2, 1;

1, 6, 17, 31, 17, 4, 1;

1, 7, 26, 69, 82, 39, 2, 1;

1, 8, 37, 131, 257, 256, 65, 4, 1;

1, 9, 50, 223, 626, 1045, 730, 139, 3, 1;

1, 10, 65, 351, 1297, 3156, 4097, 2218, 261, 4, 1;

MATHEMATICA

TA[n_, k_] := DivisorSum[n, If[k == # - 1 == 0, 1, k^(# - 1)] &]; Table[T[k + 1, n - k - 1], {n, 1, 11}, {k, 0, n - 1}] // Flatten (* _Amiram Eldar_, May 07 2021 *)

Table[A[k + 1, n - k - 1], {n, 1, 11}, {k, 0, n - 1}] // Flatten (* Amiram Eldar, May 07 2021 *)

PROG

(Magma)

A:= func< n, k | (&+[k^(d-1): d in Divisors(n)]) >;

A308813:= func< n, k | A(k+1, n-k-1) >;

[A308813(n, k): k in [0..n-1], n in [1..12]]; // G. C. Greubel, Jun 26 2024

(SageMath)

def A(n, k): return sum(k^(j-1) for j in (1..n) if (j).divides(n))

def A308813(n, k): return A(k+1, n-k-1)

flatten([[A308813(n, k) for k in range(n)] for n in range(1, 13)]) # G. C. Greubel, Jun 26 2024

STATUS

approved

editing

Discussion
Wed Jun 26
19:52
G. C. Greubel: Changed T(n,k) to A(n,k) in Mma since the code is based on the array A(n,k). Added a formula to represent the antidiagonal triangle T(n,k).
#35 by Joerg Arndt at Fri May 07 05:09:41 EDT 2021
STATUS

reviewed

approved

#34 by Michel Marcus at Fri May 07 04:19:49 EDT 2021
STATUS

proposed

reviewed

#33 by Amiram Eldar at Fri May 07 03:43:28 EDT 2021
STATUS

editing

proposed

#32 by Amiram Eldar at Fri May 07 03:17:42 EDT 2021
MATHEMATICA

T[n_, k_] := DivisorSum[n, If[k == # - 1 == 0, 1, k^(# - 1)] &]; Table[T[k + 1, n - k - 1], {n, 1, 11}, {k, 0, n - 1}] // Flatten (* Amiram Eldar, May 07 2021 *)

STATUS

approved

editing