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Revision History for A317585

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Showing entries 1-10 | older changes
a(n) = number of k with 1 <= k <= n-1 such that abs(a(k) - a(n-k)) <= 2.
(history; published version)
#12 by Bruno Berselli at Thu Aug 02 11:54:24 EDT 2018
STATUS

reviewed

approved

#11 by Michel Marcus at Thu Aug 02 11:45:50 EDT 2018
STATUS

proposed

reviewed

#10 by Rémy Sigrist at Thu Aug 02 11:34:56 EDT 2018
STATUS

editing

proposed

#9 by Rémy Sigrist at Thu Aug 02 11:29:54 EDT 2018
LINKS

Rémy Sigrist, <a href="/A317585/b317585.txt">Table of n, a(n) for n = 1..10000</a>

STATUS

approved

editing

Discussion
Thu Aug 02
11:34
Rémy Sigrist: added b-file
#8 by Susanna Cuyler at Thu Aug 02 08:01:23 EDT 2018
STATUS

proposed

approved

#7 by Rémy Sigrist at Thu Aug 02 01:19:02 EDT 2018
STATUS

editing

proposed

#6 by Rémy Sigrist at Wed Aug 01 12:23:35 EDT 2018
FORMULA

For n = 5:

- |a(1) - a(4)| = |0 - 3| = 3 > 2,

- |a(2) - a(3)| = |1 - 2| = 1 <= 2,

- |a(3) - a(2)| = |2 - 1| = 1 <= 2,

- |a(4) - a(1)| = |3 - 0| = 3 > 2,

- hence a(5) = 2.

#5 by Rémy Sigrist at Wed Aug 01 07:21:15 EDT 2018
LINKS

Rémy Sigrist, <a href="/A317585/a317585.png">Colored scatterplot of the first 100000 terms</a> (where the color is function of the parity of n)

#4 by Rémy Sigrist at Wed Aug 01 07:09:31 EDT 2018
COMMENTS

See A317420 for similar sequences.

CROSSREFS

Cf. A317420.

#3 by Rémy Sigrist at Wed Aug 01 07:03:40 EDT 2018
PROG

(PARI) a = vector(75); for (n=1, #a, a[n] = sum(k=1, n-1, abs(a[k]-a[n-k])<=2); print1 (a[n] ", "))