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Revision History for A341533

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Showing entries 1-10 | older changes

A341533

Square array T(n,k), n >= 1, k >= 1, read by antidiagonals, where T(n,k) = sqrt( Product_{a=1..n} Product_{b=1..k} (4*sin((2*a-1)*Pi/(2*n))^2 + 4*sin((2*b-1)*Pi/k)^2) ).
(history; published version)

#26 by Vaclav Kotesovec at Sun Feb 14 05:52:08 EST 2021

STATUS

reviewed

approved

#25 by Joerg Arndt at Sun Feb 14 04:56:26 EST 2021

STATUS

proposed

reviewed

#24 by Vaclav Kotesovec at Sun Feb 14 04:08:17 EST 2021

STATUS

editing

proposed

Discussion

Sun Feb 14

04:16

Seiichi Manyama: @Vaclav Kotesovec: I forgot it. Thanks. It's OK.

#23 by Vaclav Kotesovec at Sun Feb 14 04:07:54 EST 2021

CROSSREFS

Columns 1..7 give A, A007395, A341543, A231087, A341544, A231485, A341545, A230033.

STATUS

proposed

editing

Discussion

Sun Feb 14

04:08

Vaclav Kotesovec: OK ?

#22 by Seiichi Manyama at Sun Feb 14 03:47:19 EST 2021

STATUS

editing

proposed

#21 by Seiichi Manyama at Sun Feb 14 03:45:07 EST 2021

PROG

(PARI) default(realprecision, 120);

(PARI) T(n, k) = round(sqrt(prod(a=1, n, prod(b=1, k, 4*sin((2*a-1)*Pi/(2*n))^2+4*sin((2*b-1)*Pi/k)^2))));

#20 by Seiichi Manyama at Sun Feb 14 03:21:06 EST 2021

NAME

Square array T(n,k), n >= 1, k >= 1, read by antidiagonals, where T(0,k) = 2^k and T(n,k) = sqrt( Product_{a=1..n} Product_{b=1..k} (4*sin((2*a-1)*Pi/(2*n))^2 + 4*sin((2*b-1)*Pi/k)^2) ).

#19 by Seiichi Manyama at Sun Feb 14 02:40:35 EST 2021

PROG

(PARI) T(n, k) = round(sqrt(prod(a=1, n, prod(b=1, k, 4*sin((2*a-1)*Pi/(2*n))^2+4*sin((2*b-1)*Pi/k)^2))));

#18 by Seiichi Manyama at Sun Feb 14 02:39:08 EST 2021

DATA

2, 8, 2, 14, 36, 2, 36, 50, 200, 2, 82, 256, 224, 1156, 2, 200, 722, 2916, 1058, 6728, 2, 478, 2916, 9922, 38416, 5054, 39204, 2, 1156, 10082, 80000, 155682, 527076, 24200, 228488, 2, 2786, 38416, 401998, 2775556, 2540032, 7311616, 115934, 1331716, 2

#17 by Seiichi Manyama at Sun Feb 14 02:36:32 EST 2021

CROSSREFS

Main diagonal gives A341535.