The On-Line Encyclopedia of Integer Sequences (OEIS)

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Revision History for A366435

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A366435

G.f. A(x) satisfies A(x) = 1 + x * ((1 - x) / A(x))^(5/2).
(history; published version)

#10 by Michel Marcus at Tue Oct 10 05:09:04 EDT 2023

STATUS

reviewed

approved

#9 by Joerg Arndt at Tue Oct 10 05:03:34 EDT 2023

STATUS

proposed

reviewed

#8 by Seiichi Manyama at Tue Oct 10 03:49:07 EDT 2023

STATUS

editing

proposed

#7 by Seiichi Manyama at Mon Oct 09 23:11:42 EDT 2023

CROSSREFS

Partial sums give A366405.

#6 by Seiichi Manyama at Mon Oct 09 22:50:59 EDT 2023

FORMULA

a(n) = (-1)^(n-1) * Sum_{k=0..n} binomial(7*k/2-1,k) * binomial(5*k/2,n-k) / (7*k/2-1).

#5 by Seiichi Manyama at Mon Oct 09 22:50:36 EDT 2023

DATA

1, 1, -5, 25, -160, 1150, -8851, 71345, -594530, 5080300, -44272760, 391961328, -3515490820, 31874449160, -291676084205, 2690284784605, -24985250240043, 233447554879855, -2192862233710505, 20696454624488125, -196168344717398010, 1866499116495323946

#4 by Seiichi Manyama at Mon Oct 09 22:49:59 EDT 2023

PROG

(PARI) a(n) = (-1)^(n-1)*sum(k=0, n, binomial(7*k/2-1, k)*binomial(5*k/2, n-k)/(7*k/2-1));

#3 by Seiichi Manyama at Mon Oct 09 22:37:50 EDT 2023

CROSSREFS

Cf. A366431, A366432, A366433, A366434, A366436, A366437.

#2 by Seiichi Manyama at Mon Oct 09 22:29:54 EDT 2023

NAME

allocated for Seiichi Manyama

G.f. A(x) satisfies A(x) = 1 + x * ((1 - x) / A(x))^(5/2).

DATA

1, 1, -5, 25, -160, 1150, -8851, 71345, -594530, 5080300, -44272760, 391961328, -3515490820, 31874449160, -291676084205, 2690284784605, -24985250240043, 233447554879855

OFFSET

0,3

KEYWORD

allocated

sign

AUTHOR

Seiichi Manyama, Oct 09 2023

STATUS

approved

editing

#1 by Seiichi Manyama at Mon Oct 09 22:29:54 EDT 2023

NAME

allocated for Seiichi Manyama

KEYWORD

allocated

STATUS

approved