Displaying 1-6 of 6 results found.
page
1
Multiplicative with a(p^e) = 1 if p > e, otherwise 0.
+10
28
1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1
FORMULA
Multiplicative with a(p^e) = [e < p], where [ ] is the Iverson bracket.
Sum_{k=1..n} a(k) ~ c * n, where c = Product_{p prime} (1 - 1/p^p) = 0.7219902344... . - Amiram Eldar, Jan 07 2023
MATHEMATICA
f[p_, e_] := If[e < p, 1, 0]; a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Jan 06 2023 *)
PROG
(PARI) A359550(n) = { my(f = factor(n)); prod(k=1, #f~, (f[k, 2]<f[k, 1])); };
(Python)
from sympy import factorint
def A359550(n): return int(all(map(lambda d:d[0]>d[1], factorint(n).items()))) # Chai Wah Wu, Jan 06 2023
CROSSREFS
Characteristic function of A048103.
a(n) = 1 if k-th arithmetic derivative of n is zero for some k, otherwise 0.
+10
16
1, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 1
LINKS
Michael De Vlieger, Bitmap of a(n), n = 0..2^24, 2048 X 2048 pixels, with 0 in white and 1 in black. Furnishes 4260302 terms of A099308.
FORMULA
For prime p, a(p) = 1, a(p^p * m) = 0, for all m >= 1. a(4m) = 0 for m > 0. - Michael De Vlieger, Jan 04 2023
a(0) = 1; and for n > 0, a(n) = A359550(n) * a( A003415(n)). [Provided that Conjecture 3 given on page 5 of Ufnarovski and Åhlander 2003 paper holds, i.e., that map x -> x' never forms nontrivial loops]
(End)
MATHEMATICA
w = {}; nn = 2^10; k = 1; While[Set[m, #^#] <= nn &[Prime[k]], AppendTo[w, m]; k++]; a3415[n_] := a3415[n] = Which[Abs@ n < 2, 0, PrimeQ[n], 1, True, n Total[#2/#1 & @@@ FactorInteger[Abs@ n]]]{1, 1}~Join~Reap[Do[Which[PrimeQ[n], Sow[1], MemberQ[w, n], Sow[0], True, If[NestWhileList[a3415, n, And[! Divisible[#, 4], FreeQ[w, #]] &, 1][[-1]] == 0, Sow[1], Sow[0]]], {n, 2, nn}]][[-1, -1]] (* Michael De Vlieger, Jan 04 2023 *)
(* 2nd program: generate m <= 2^24 terms of the sequence from the bitmap above: *)
m = 10^3; Flatten[ImageData[Import["https://oeis.org/ A328308/a328308.png"], "Bit"]][[1 ;; m]] /. {0 -> 1, 1 -> 0} (* Michael De Vlieger, Jan 04 2023 *)
PROG
(PARI)
A003415checked(n) = if(n<=1, 0, my(f=factor(n), s=0); for(i=1, #f~, if(f[i, 2]>=f[i, 1], return(0), s += f[i, 2]/f[i, 1])); (n*s));
A328308(n) = if(!n, 1, while(n>1, n = A003415checked(n)); (n));
CROSSREFS
Characteristic function of A099308.
Cf. A003415, A099309 (positions of zeros), A256750, A328306 [= a( A276086(n))], A328309 (partial sums), A341996, A341999 (one's complement), A342023, A351071, A359541 (inverse Möbius transform), A359543, A359546, A359550, A368915.
a(n) = 1 if the k-th arithmetic derivative is nonzero for all k >= 0, otherwise 0.
+10
13
0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 1, 1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 1, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 0, 1, 0, 1, 0
COMMENTS
Characteristic function of A099309.
FORMULA
a(n) = 1 if n is in A100716 or ends there by repeated applications of A003415, otherwise a(n) = 0 (when n instead reaches 0 by such iteration).
For all n > 0, a(n) = [ A256750(n) < 1].
For all n > 0, a(n) >= [ A129251(n)>0], i.e., if A129251(n) is nonzero, then certainly a(n) = 1.
For all n > 1, a(n) >= [ A341997(n) > 1].
PROG
(PARI)
A003415checked(n) = if(n<=1, 0, my(f=factor(n), s=0); for(i=1, #f~, if(f[i, 2]>=f[i, 1], return(0), s += f[i, 2]/f[i, 1])); (n*s));
A341999(n) = if(!n, n, while(n>1, n = A003415checked(n)); (!n));
a(n) = 1 if there is a prime p such that p^p divides n, otherwise 0.
+10
8
0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1
FORMULA
a(n) = min(1, A129251(n)) = [ A129251(n) > 0], where [ ] is the Iverson bracket.
For all n >= 1,
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = 1 - Product_{p prime} (1 - 1/p^p) = 0.2780097655... . - Amiram Eldar, Jul 24 2022
MATHEMATICA
Array[Function[{D, q}, Boole[Total@ Table[Count[D, _?(IntegerExponent[#, p] == p &)], {p, Prime@ Range@ q}] > 0]] @@ {Divisors[#], PrimePi@ Floor[Sqrt[#]]} &, 120] (* Michael De Vlieger, Mar 11 2021 *)
PROG
(PARI) A342023(n) = if(1==n, 0, my(f = factor(n)); for(k=1, #f~, if(f[k, 2]>=f[k, 1], return(1))); (0));
(Python)
from sympy import factorint
f = factorint(n)
for p in f:
if p <= f[p]:
return 1
CROSSREFS
Characteristic function of A100716.
Cf. A003415, A008966, A048103 (positions of zeros), A107078, A276086, A341996, A341999, A327936, A341999, A342004, A342007, A359546, A359550 (one's complement).
Differs from A129251 and A276077 for the first time at n=108, as here a(108) = 1.
Differs from A342024 for the first time at n=625, where a(625)=0, while A342024(625)=1.
a(n) = 1 if A359542(n) = 0, otherwise a(n) = 0.
+10
5
1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 1, 1, 0, 1, 1, 0, 0, 1, 1, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 1
COMMENTS
Question: What can be said about the distribution of 0's and 1's in this sequence? Compare also to A328308 and A359546.
FORMULA
a(n) = [ A359542(n) == 0], where [ ] is the Iverson bracket.
PROG
(PARI)
A003415checked(n) = if(n<=1, 0, my(f=factor(n), s=0); for(i=1, #f~, if(f[i, 2]>=f[i, 1], return(0), s += f[i, 2]/f[i, 1])); (n*s));
A341999(n) = if(!n, n, while(n>1, n = A003415checked(n)); (!n));
CROSSREFS
Characteristic function of A359544.
Numbers such that they are not divisible by p^p for any prime p, but for some k-th arithmetic derivative (k >= 1) of n such a factor exists.
+10
5
15, 26, 35, 39, 45, 50, 51, 55, 63, 69, 74, 75, 86, 87, 90, 91, 95, 99, 102, 106, 110, 111, 115, 117, 119, 122, 123, 125, 133, 134, 141, 143, 146, 147, 153, 155, 158, 159, 169, 171, 175, 178, 183, 187, 190, 194, 195, 198, 203, 207, 210, 213, 215, 218, 219, 225, 226, 230, 234, 235, 245, 247, 249, 250
LINKS
Michael De Vlieger, 4096 X 4096 pixel raster with origin (0, 0) in the upper left corner and black pixels at (x, y), indicate a number 4096*(y-1) + (x-1) in this sequence. Thus this image contains 7852685 terms of this sequence.
EXAMPLE
15 = 3*5 is present, as although it itself is not in A100716, its arithmetic derivative 15' = 8 is there.
26 = 2*13 is present, as although neither 26 nor 26' = 15 are in A100716, its second derivative = 26'' = 15' = 8 is there.
MATHEMATICA
f[n_] := f[n] = Which[Abs@ n < 2, 0, PrimeQ[n], 1, True, n Total[#2/#1 & @@@ FactorInteger[Abs@ n]]]; g[n_] := And[n > 0, AnyTrue[FactorInteger[n], #2 >= #1 & @@ # &]]; w = {}; nn = 2^16; k = 1; While[Set[m, #^#] <= nn &[Prime[k]], AppendTo[w, m]; k++]; Reap[Do[If[! g[n], If[g@ NestWhile[f, n, And[! Divisible[#, 4], FreeQ[w, #]] &], Sow[n] ] ], {n, 2, nn}] ][[-1, -1]]
(* or, generate up to 7852685 terms of this sequence from the bitmap by setting y to a number not exceeding 4096: *)
With[{img = https://oeis.org/ A359547/a359547.png, y = 2}, Map[4096 (#1 - 1) + #2 - 1 & @@ # &, Position[ImageData[img][[1 ;; y, All]], 0.]] ] (* Michael De Vlieger, Jan 23 2023 *)
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