FIXED POINT FREE MAPPINGS WHICH SATISFY A DARBO
TYPE CONDITION
ELISABETTA MALUTA, STANISLAW PRUS, AND JACEK WOŚKO
Abstract. We give constructions of continuous mappings on normed spaces which
satisfy a Darbo type condition with respect to a measure of noncompactness and do
not have fixed points or even have positive minimal displacement. An estimate for the
minimal displacement is given.
Introduction
In [13], Lin and Sternfeld proved that if a bounded closed convex subset C of a Banach
space is not compact, then there exists a lipschitzian mapping F : C → C with positive
minimal displacement. Additionally F can be chosen in such a way that its Lipschitz
constant is arbitrarily close to 1. Moreover, various estimates of minimal displacement
of lipschitzian mappings in terms of the Lipschitz constant are known (see [10]).
Instead of the Lipschitz condition some authors consider an analogous condition in
which measures of noncompactness of a set and its image are compared. The best constant in this condition is called µ-norm of a mapping, where µ is a given measure of
noncompactness. In particular, Darbo [5] proved a counterpart of the well-known Banach contraction principle for mappings with µ-norm less than 1. Using the result of
Lin and Sternfeld it is easy to show that if a measure µ is equivalent to the Kuratowski
measure, then for each bounded closed convex subset C of a Banach space which is not
compact there exist lipschitzian mappings F : C → C with positive minimal displacement whose µ-norms are arbitrarily close to 1 (see [4]). On the other hand, Darbo’s
theorem implies that a continuous mapping with µ-norm one does not have positive
minimal displacement. Other applications of measures of noncompactness to minimal
displacement problems can be found in [12] and [16].
Measures of noncompactness appear also in the spectral theory (see for instance [8]).
A coefficient introduced in this theory motivated some authors to study the infimum of
µ-norms of fixed point free continuous mappings of the unit ball of an infinite dimensional
Banach space (see [18]). Darbo’s theorem shows that it is not less than 1 and in [1] it
was proved that for an arbitrary measure of noncompactness µ there exists a fixed point
free continuous mapping of the unit ball whose µ-norm equals 1. The method used in
[1] works actually not only for the unit ball but for any set with nonempty interior. In
[19] and [1] estimates for the minimal displacement of continuous mappings satisfying a
Darbo type condition are also given. Again the results concern only the unit ball or sets
containing balls.
In this paper we give some constructions of fixed point free continuous mappings for
arbitrary convex subsets of a normed space. In the case when µ is the Kuratowski or
2000 Mathematics Subject Classification. 47H09, 47H10.
Key words and phrases. Measures of noncompactness, Darbo type conditions, minimal displacement.
1
2
E. MALUTA, S. PRUS, AND J. WOŚKO
separation measure of noncompactness we obtain mappings with µ-norm one without any
additional assumption. If µ is the Hausdorff measure we need to consider weakly compact
subsets of Banach spaces with the non-strict Opial property. These results can be seen
as analogs of the Lin–Sternfeld theorem, but in this case the minimal displacement of
the resulting mappings is zero. Actually our construction gives mappings which are
asymptotically regular. Mappings with this property were also obtained in [1] but only
on the unit ball of a Banach space with a special basis.
In the last part of the paper we study the minimal displacement problem. We begin
with the case of unbounded sets. The authors are indebted to T. Kuczumow for suggesting them this problem. We show that if A is a convex unbounded subset of a normed
space X, then there exists a continuous mapping F : X → A with µ-norm zero and
arbitrarily large minimal displacement. This contrasts the result proved in [15]: each
infinite dimensional Banach space contains a closed convex unbounded set A such that
every nonexpansive self-mapping of A has minimal displacement zero.
We next consider weakly compact convex subsets A of a separable Banach space X.
We give the general construction of a continuous mapping F : X → A whose χ-norm
and minimal displacement are estimated in terms of the measure χ(A). Similar results
were obtained in [19], but they mainly concern the case when A is a ball.
1. Preliminaries
In this paper we consider real normed spaces. Let X be such space. By BX we denote
the closed unit ball of X. A general measure of noncompactness in X is defined in an
axiomatic way (see [2]). However, in this paper we will consider only specific measures.
Let A ⊂ X be a nonempty bounded set. The Kuratowski measure of noncompactness
α(A) is defined as the infimum of all d > 0 such that A may be covered with finitely
many sets with diameters at most d. Similarly, the Hausdorff measure of noncompactness
χ(A) is defined as the infimum of all r > 0 such that A may be covered with finitely
many balls with radii at most r. Let now (xn ) be a sequence in X. We put sep(xn ) =
inf{kxi − xj k : i 6= j}. The third standard measure of noncompactness is called the
separation measure. It is defined by the formula
β(A) = sup{sep(xn ) : (xn ) ⊂ A}.
These measures are equivalent. More precisely, the following inequalities hold
χ(A) ≤ β(A) ≤ α(A) ≤ 2χ(A).
A subset A of a normed space X is called totally bounded if for every ǫ > 0 there is a
finite ǫ-net for A. If A is relatively compact, then A is totally bounded and for Banach
spaces also the opposite implication holds. Let µ ∈ {α, β, χ}. Clearly, a bounded set A
is totally bounded if and only if µ(A) = 0.
Let D be a nonempty subset of a normed space X. A mapping F : D → X is
nonexpansive if it has Lipschitz constant one. Given a measure of noncompactness µ in
X, we say that F satisfies a Darbo type condition if there exists a constant L ≥ 0 such
that
(1)
µ(F (C)) ≤ Lµ(C)
for every bounded set C ⊂ D. By [F ]µ we denote the infimum of all such constants
L. We call it µ-norm of F . Clearly, condition (1) holds also with L = [F ]µ . In the
FIXED POINT FREE MAPPINGS WHICH SATISFY A DARBO TYPE CONDITION
3
terminology of [2], a continuous mapping F satisfying condition (1) is said to be L-µcontractive. In case µ = α the term L-set-contractive is also used. Darbo [5] proved that
if D is a bounded closed convex subset of a Banach space and a continuous mapping
F : D → D satisfies the condition [F ]α < 1, then F has a fixed point. This result holds
also for abstract measures of noncompactness (see [2]).
Given a mapping F : D → X, by the minimal displacement of F we mean the number
d(F ) = inf{kx − F (x)k : x ∈ D}.
A mapping F : D → X is said to be asymptotically regular if
lim kF n+1 (x) − F n (x)k = 0
n→∞
for every x ∈ D. Of course in this case d(F ) = 0. Curves are our main tool for
constructing mappings with appropriate properties. By a curve in a normed space X we
mean a continuous mapping Γ : I → X where I is an interval of the real line R. In this
paper we will consider only the case when I is of the form [a, +∞). A curve is simple if
it is one-to-one. We will identify a curve Γ with its image Γ(I).
2. Mappings without fixed points
To prove the main theorem of this section we need the following lemma.
Lemma 2.1. Let X be a normed space and µ ∈ {α, β}. If a bounded convex set A ⊂ X
is not totally bounded, then there exists a simple curve Γ in A such that
µ(G) = µ(Γ)
for every set G ⊂ Γ which is not totally bounded.
Proof. We can assume that 0 ∈ A and diam A ≤ 1. There exist r > 0 and a sequence
(xn )∞
n=0 in A such that
(2)
dist (xn , span{x0 , . . . , xn−1 }) ≥ r
for every n ∈ N (see [11, Lemma 19.4]). Passing to a subsequence, we can assume that
for any numbers a1 , a2 , a3 , a4 ∈ R the following limit exists
lim
n1 <···<n4
n1 →∞
4
X
ai xni
i=1
(see [3] or [7, Proposition 19.17]). Given t ∈ [0, 1], we now put
ϕ(t) = lim k(1 − t)xn−1 + txn − (1 − t)xm − txm+1 k.
n<m
n→∞
From (2) we see that ϕ(t) ≥ rt. Next,
r(1 − t) ≤ k(1 − t)xm − ((1 − t)xn−1 + txn )k
≤ ktxm+1 + (1 − t)xm − ((1 − t)xn−1 + txn )k + tkxm+1 k
1
≤ 1+
ktxm+1 + (1 − t)xm − ((1 − t)xn−1 + txn )k
r
whenever n < m. Consequently,
c
ϕ(t) ≥ c max{t, 1 − t} ≥
2
4
E. MALUTA, S. PRUS, AND J. WOŚKO
where c = r2 /(1 + r).
We set
c
((1 − t)xn + txn+1 )
2ϕ(t)
where t ∈ [0, 1] and n = 0, 1, 2, . . . . Obviously, Γn (t) ∈ A and
c
(3)
lim kΓn−1 (t) − Γm (t)k =
n<m
2
n→∞
Γn (t) =
for every t ∈ [0, 1]. Next,
ϕ(t)
ϕ(t)
kΓn (t) − Γn (s)k ≤ Γn (t) −
Γn (t) +
Γn (t) − Γn (s)
ϕ(s)
ϕ(s)
1
1
1
c
−
|t − s| kxn+1 − xn k
kΓn (t)k +
≤
2 ϕ(t) ϕ(s)
ϕ(s)
2
≤ |ϕ(t) − ϕ(s)| + |t − s|
c
for every n = 0, 1, 2, . . . and all t, s ∈ [0, 1]. Moreover,
|ϕ(t) − ϕ(t)| ≤ 2|t − s|,
so we finally obtain the inequality
kΓn (t) − Γn (s)k ≤ M |t − s|
(4)
where M = 4/c + 1.
We define the desired curve in A by the formula
Γ(s) = Γ⌊s⌋ ({s})
where s ∈ [0, +∞), ⌊s⌋ = max{n ∈ Z : n ≤ s} and {s} = s − ⌊s⌋. We shall show
that if (yn ) is a sequence on Γ without a convergent subsequence, then there exists a
subsequence (ynk ) for which
c
(5)
lim kyni − ynk k = .
i<k
2
i→∞
Observe that if yn = Γ(sn ), then limn→∞ sn = +∞. Consequently, limn→∞ ⌊sn ⌋ = +∞,
so there exists a subsequence (snk ) such that ⌊snk ⌋ + 1 < ⌊snk+1 ⌋ for every k ∈ N and
({snk }) converges to some t ∈ [0, 1]. From (4) we obtain
kΓ(snk ) − Γ(⌊snk ⌋ + t)k ≤ M |{snk } − t|
for every k ∈ N which shows that
lim kΓ(snk ) − Γ(⌊snk ⌋ + t)k = 0.
k→∞
This and (3) give
lim kyni − ynk k = lim kΓ(⌊sni ⌋ + t) − Γ(⌊snk ⌋ + t)k
i<k
i→∞
i<k
i→∞
= lim kΓ⌊sni ⌋ (t) − Γ⌊snk ⌋ (t)k =
i<k
i→∞
c
.
2
Consider now a set G ⊂ Γ with µ(G) > 0. There exists a sequence (yn ) in G which
does not have a convergent subsequence. We can therefore find a subsequence (ynk ) for
FIXED POINT FREE MAPPINGS WHICH SATISFY A DARBO TYPE CONDITION
5
which formula (5) holds. For every ǫ > 0 there is m ∈ N such that sep(ynk )∞
k=m ≥ c/2−ǫ.
This shows that β(G) ≥ c/2.
Since β(G) ≤ α(G) ≤ α(Γ), it suffices to check that α(Γ) ≤ c/2. For this purpose
we take an arbitrary ǫ > 0 and choose 0 < t1 < · · · < tN < 1 such that for every
t ∈ [0, 1] there exists k with |t − tk | < ǫ/(3M ). By (3), there exists m0 ∈ N such that if
m0 < n < m, then
ǫ
c
kΓ(n − 1 + tk ) − Γ(m + tk )k −
<
2
3
for any k = 1, . . . , N . We set
n
ǫ o
Ak = Γ(m0 + 2p + t) : p ∈ N, t ∈ [0, 1], |t − tk | <
3M
n
ǫ o
AN +k = Γ(m0 + 2p − 1 + t) : p ∈ N, t ∈ [0, 1], |t − tk | <
3M
where k = 1, . . . , N . Let s1 , s2 ∈ [0, 1] be such that there is k ∈ {1, . . . , N } for which
|si − tk | < ǫ/(3M ) for i = 1, 2. Then from (4) we obtain
ǫ
kΓ(n + si ) − Γ(n + tk )k <
3
for every n ∈ N and i = 1, 2. This shows that
2ǫ
kΓ(n + s1 ) − Γ(n + s2 )k < .
3
Moreover, if n, m ∈ N, n, m > m0 and |n − m| > 1, then
kΓ(n + s1 ) − Γ(m + s2 )k <
2ǫ
c
+ kΓ(n + tk ) − Γ(m + tk )k < + ǫ.
3
2
It follows that
diam Ak ≤
c
+ǫ
2
for every k = 1, . . . , 2N .
Clearly,
{Γ(s) : s > m0 } ⊂
2N
[
Ak
k=1
and the set {Γ(s) : s ≤ m0 } is compact. This shows that α(Γ) ≤ c/2 which completes
the proof.
Now we can prove our theorem.
Theorem 2.2. Let X be a normed space and µ ∈ {α, β}. If a bounded convex set
A ⊂ X is not totally bounded, then there exists a continuous mapping F : X → A such
that [F ]µ = 1, F is asymptotically regular and F does not have a fixed point.
Proof. Consider the curve Γ in A constructed in the proof of Lemma 2.1. Observe that
dist(xn+2 , Γn ) > 0 for every n = 0, 1, 2, . . . . We can therefore find a sequence (ǫn )∞
n=0
converging to 0 with 0 < ǫn < dist(xn+2 , Γn ) for every n. We use a modification of a
construction given in [18]. Namely, we set
Tn = {x ∈ X : dist(x, Γn ) ≤ ǫn },
T =
∞
[
n=0
Tn ,
Dn =
n
[
k=0
Tk ∪ (X \ Int T )
6
E. MALUTA, S. PRUS, AND J. WOŚKO
where n = 0, 1, 2, . . . . By induction we shall construct a sequence of continuous functions
fn : Dn → [0, n + 2] such that fn (Γ(t)) = t if Γ(t) ∈ Dn , fn (x) = 0 if x ∈ X \ Int T
and fn+1 is an extension of fn . As the first step, we set ψ0 (Γ(t)) = t if Γ(t) ∈ D0 , and
ψ0 (x) = 0 if x ∈ X \ Int T . Using the Urysohn lemma, we extend ψ0 to a continuous
function f0 : D0 → [0, 2].
Assuming that the desirable functions f0 , . . . , fn have been found, we put ψn+1 (Γ(t)) =
t if Γ(t) ∈ Dn+1 \ Dn and ψn+1 (x) = fn (x) if x ∈ Dn . A continuous extension fn+1 :
Dn+1 → [0, n + 3] of ψn+1 has the required properties.
Now we define f : X → [0, +∞) in the following way. If x ∈ X, then x ∈ Dn for some
n ∈ N∪{0} and we set f (x) = fn (x). The function f is continuous and f (Dn ) ⊂ [0, n+2]
1
for each n ∈ N ∪ {0}. Next we define g : [0, +∞) → Γ by the formula g(t) = Γ t + 1+t
.
We claim that F = g ◦ f has the required properties. Suppose that F (x) = x. Then
1
x = Γ(s) for some s ∈ [0, +∞), so F (x) = g(f (x)) = g(s) = Γ s + 1+s
. Hence
1
Γ s + 1+s = Γ(s) which contradicts the fact that Γ does not have a double point.
Therefore F has no fixed point.
Moreover, F (Γ) = {Γ(s) : s ≥ 1}, so µ(F (Γ)) = µ(Γ). This shows that [F ]µ ≥ 1.
To prove the opposite inequality consider a bounded set C ⊂ X and put C0 = C ∩ T .
Then F (C) \ F (C0 ) is empty or a singleton. Assume that µ(F (C)) > 0. It follows
that C0 \ Dn 6= ∅ for every n ∈ N ∪ {0}. We can therefore find an increasing sequence
of positive integers (mk ) and a sequence (vk ) in C0 such that vk ∈ Tmk for every k.
Given k ∈ N we choose yk ∈ Γmk with kvk − yk k ≤ ǫk . Then (yk ) does not have a
convergent subsequence, so there exists a subsequence (ynk ) for which formula (5) holds.
Consequently, limi<k kvni − vnk k = c/2. Hence for every ǫ > 0 there exists m ∈ N such
that sep(vnk )∞
k=m ≥ c/2 − ǫ. Therefore c/2 ≤ β(C0 ) ≤ µ(C0 ). This and the proof of
Lemma 2.1 show that
c
µ(F (C)) = ≤ µ(C0 ) ≤ µ(C).
2
Hence [F ]µ ≤ 1 and we finally see that [F ]µ = 1.
To show that F is asymptotically regular we take x ∈ X and put F n (x) = Γ(tn ).
Then tn+1 = tn + 1/(1 + tn ) for every n ∈ N, so the sequence (tn ) tends to infinity and
consequently, limn→∞ (tn+1 − tn ) = 0. In particular tn+1 − tn < 1 for n large enough. For
such n either ⌊tn+1 ⌋ = ⌊tn ⌋ or ⌊tn+1 ⌋ − 1 ≤ tn < ⌊tn+1 ⌋. Applying (4), in the first case
we see that
kF n+1 (x) − F n (x)k ≤ M (tn+1 − tn )
and in the second case
kF n+1 (x) − F n (x)k ≤ M (tn+1 − ⌊tn+1 ⌋) + M (⌊tn+1 ⌋ − tn ) = M (tn+1 − tn ).
This shows that limn→∞ kF n+1 (x) − F n (x)k = 0.
Let us recall that χ(A) = α(A)/2 for any bounded set A in the space l∞ (see [2, p. 24]).
Consequently, Theorem 2.2 holds for l∞ also with µ = χ. In general when considering
Hausdorff measure, we obtain similar results under the additional hypothesis that X has
the non-strict (or weak) Opial property, i.e. if for every weakly null sequence (xn ) in X
and every x ∈ X we have
lim inf kxn k ≤ lim inf kx + xn k.
n→∞
n→∞
FIXED POINT FREE MAPPINGS WHICH SATISFY A DARBO TYPE CONDITION
7
Theorem 2.3. Let X be a Banach space which has the non-strict Opial property. If
a convex weakly compact subset A of X is not compact, then there exists a continuous
mapping F : X → A such that [F ]χ = 1, F is asymptotically regular and F does not
have a fixed point.
Proof. We can assume that A contains a sequence (xn )∞
n=0 which is weakly null but
inf{kxn k : n = 0, 1, . . . } > 0. Passing to a subsequence if necessary, we may assume that
it is a basic sequence (see [14]). Then
cn = inf {k(1 − t)xm + txm+1 k : t ∈ [0, 1], m ≥ n} > 0
for every n. We set
Γn (t) =
cn
((1 − t)xn + txn+1 )
k(1 − t)xn + txn+1 k
where t ∈ [0, 1] and n = 0, 1, 2, . . . . Clearly, Γn (t) ∈ A and the formula
Γ(s) = Γ⌊s⌋ ({s}),
where s ≥ 0, defines a simple curve in A. We have kΓ(s)k ≤ supn≥0 cn = limn→∞ cn for
every s ≥ 0, which in particular shows that χ(Γ) ≤ limn→∞ cn .
Now we proceed as in the proof of Theorem 2.2 and obtain a continuous mapping
F : X → A which is asymptotically regular but does not have a fixed point. We
need only to show that [F ]χ ≤ 1. To this end we consider a set C0 ⊂ T such that
χ(F (C0 )) > 0, where T is the set constructed in the proof of Theorem 2.2. Then there
exist an increasing sequence of positive integers (mk ) and points vk ∈ C0 , yk ∈ Γmk with
kvk − yk k ≤ ǫk . Clearly, the sequence (yn ) is weakly null, so
lim inf kx − vn k = lim inf kx − yn k ≥ lim inf kyn k = lim cn
n→∞
n→∞
n→∞
n→∞
for every x ∈ X. Moreover,
n
o
χ(C0 ) ≥ χ({vn : n ∈ N}) ≥ inf lim inf kx − vn k : x ∈ X .
n→∞
It follows that χ(F (C0 )) ≤ χ(Γ) ≤ χ(C0 ).
3. Mappings with positive minimal displacement
In our next theorem we deal with unbounded sets. In [15], it was proved that each
infinite dimensional Banach space X contains an unbounded convex closed set A such
that d(F ) = 0 for every nonexpansive mapping F : A → A. In the case when X
is reflexive a simple characterization of such sets A was given in [17]. Namely, they
are linearly bounded, i.e., the intersections of A with all lines are bounded. The case of
mappings satisfying a Darbo type condition is completely different. Indeed, we will show
that for every unbounded convex set there exists a continuous mapping with µ-norm zero
and positive minimal displacement.
Theorem 3.1. Let A be a convex unbounded subset of a Banach space X. For every
ǫ > 0 there exists a continuous mapping F : X → A such that d(F ) ≥ ǫ and if a set
C ⊂ X is bounded, then F (C) is relatively compact.
8
E. MALUTA, S. PRUS, AND J. WOŚKO
Proof. The set A is not bounded, so there exists a norm-one linear functional x∗ on X
for which sup{x∗ (x) : x ∈ A} = +∞. We can therefore find a sequence (xn ) in A such
that x∗ (x1 ) > 2ǫ and x∗ (xn+1 ) ≥ 2x∗ (xn ) for every n ∈ N. Clearly,
k(1 − t)xn + txn+1 − ((1 − s)xm + sxm+1 ) k ≥ x∗ (xn ) − x∗ (xm+1 ) > 2ǫ
whenever t, s ∈ [0, 1] and n > m+1. Consequently, the segments Γn (t) = (1−t)xn +txn+1
where n ∈ N, t ∈ [0, 1], give us a simple curve Γ in A.
We now follow the idea used in the proof of Theorem 1 in [19]. Namely, we put
Gn = {x ∈ X : dist(x, Γn ) ≤ ǫ}, Tn = {x ∈ X : dist(x, Γn ) ≤ 2ǫ}
S
S∞
where n ∈ N, G = ∞
G
,
and
T
=
n
n=1
n=1 Tn . Using the Urysohn lemma we find a
continuous function g : G → [1, +∞) such that g(Gn ) ⊂ [n, n + 1] and g(x) = n + 1
for every x ∈ Gn ∩ Gn+1 and every n ∈ N. Next, a construction similar to that in the
proof of Theorem 2.2 gives us a continuous extension f : X → [1, +∞) of g for which
f (x) = 1 for every x ∈ X \ T and f (Tn ) ⊂ [1, n + 3] for every n ∈ N. We finally put
F (x) = Γ(f (x) + 2) for each x ∈ X.
If x ∈ X \ G, then dist(x, Γ) > ǫ and in particular kx − F (x)k > ǫ. If in turn x ∈ G,
then x ∈ Gn for some n ∈ N. Consequently, there exists y ∈ Γn such that kx − yk ≤ ǫ.
But F (Gn ) ⊂ Γn+2 , so ky − F (x)k > 2ǫ which shows that kx − F (x)k > ǫ. We therefore
see that d(F ) ≥ ǫ.
Given r S
> 0, we can find m ∈ N so that Tn ⊂ X \ rBX for every n ≥ m. Then
F (rBX ) ⊂ m+1
k=3 Γk which shows that the set F (rBX ) is relatively compact.
In [9], an upper estimate for the minimal displacement in terms of the α-norm was
obtained. Namely, given a bounded subset A of a normed space X, by χ0 (A) we denote
the inner Hausdorff measure of noncompactness of A, i.e. χ0 (A) is the infimum of all
r > 0 such that A may be covered with finitely many balls with centers in A and radii
at most r. Then
1
d(F ) ≤ 1 −
χ0 (C)
[F ]α
for every continuous mapping F : C → C, where C is a bounded convex subset of X. In
the last part of our paper we will obtain a lower estimate for the minimal displacement.
For this purpose we need two preliminary results.
Lemma 3.2. Let X be a separable Banach space and let A ⊂ X be convex and weakly
compact but not compact. Then there exists a simple curve Γ in A such that
1
lim inf kx − Γ(t)k ≥ χ(A)
t→+∞
2
for every x ∈ X.
Proof.
S∞ Let (Xn ) be an ascending sequence of finite dimensional subspaces of X such that
n=1 Xn is dense in X. We can assume for simplicity that χ(A) = 1. Let c ≥ 1 be such
that kxk ≤ c for every x ∈ A. By induction we will choose a sequence (xn ) in A so that
2
n+1
for every x ∈ span (Xn ∪ {x1 , . . . , xn }). As x1 we take an arbitrary element of A. Next,
having x1 , . . . , xn , we find a finite 1/(n + 1)-net {z1 , . . . , zm } for the set Y ∩ 2cBX where
kx − xn+1 k ≥ 1 −
FIXED POINT FREE MAPPINGS WHICH SATISFY A DARBO TYPE CONDITION
9
Y = span (Xn ∪ {x1 , . . . , xn }). Since χ(A) = 1, there exists xn+1 ∈ A such that kzi −
xn+1 k ≥ 1 − 1/(n + 1) for every i = 1, . . . , m. Let now x ∈ Y . If kxk > 2c, then
kx − xn+1 k ≥ kxk − kxn+1 k > c ≥ 1.
If in turn kxk ≤ 2c, then there is i ∈ {1, . . . , m} such that kx − zi k < 1/(n + 1) and we
see that
2
1
≥1−
.
kx − xn+1 k > kzi − xn+1 k −
n+1
n+1
We find a subsequence (ym ) of (xn ) which converges weakly to some y ∈ A and such
that (ym − y) is a basic sequence (see [14]). Next, by induction we will choose an
increasing sequence (mk ) of positive integers so that
(6)
kx − ymk+1 k ≥ kx − yk −
3
k+1
for every x ∈ span (Xk ∪ {ym1 , . . . , ymk }) ∩ 2cBX . To this end we set m1 = 1 and having
ym1 , . . . , ymk , we take a finite 1/(k + 1)-net {v1 , . . . , vs } for the set Z ∩ 3cBX where
Z = span (Xk ∪ {ym1 , . . . , ymk }). Given i ∈ {1, . . . , s}, we find a norm-one functional
vi∗ ∈ X ∗ for which vi∗ (vi ) = kvi k. There exists mk+1 > mk such that
vi∗ ymk+1 − y
<
1
k+1
for every i = 1, . . . , s. Let now x ∈ Z ∩ 2cBX . Then there exists i ∈ {1, . . . , s} such that
kx − y − vi k < 1/(k + 1). Therefore,
kx − ymk+1 k > vi − ymk+1 − y
−
≥ vi∗ vi − ymk+1 − y
> kvi k −
2
k+1
≥ kx − yk −
1
k+1
−
1
k+1
3
.
k+1
Since (ymk ) is a subsequence of (xn ),
(7)
kx − ymk+1 k ≥ 1 −
2
k+1
for every x ∈ span (Xk ∪ {ym1 , . . . , ymk }). This easily implies that
(8)
lim inf kx − ymk+1 k ≥ 1
k→∞
for every x ∈ X.
Since (ymk − y) is a basic sequence, the segments
Γk (t) = (1 − t)ymk+1 + tymk ,
where t ∈ [0, 1], give us a simple curve Γ. Let x ∈ X and t ∈ [0, 1]. If kxk ≥ 2c, then
kx − Γk (t)k ≥ c > 1/2. Assume that kxk < 2c. We take ǫ ∈ (0, 2c − kxk) and find i ∈ N
10
E. MALUTA, S. PRUS, AND J. WOŚKO
and an element z ∈ Xi for which kx − zk < ǫ. Observe that kzk < 2c. If 1 − t ≥ 1/2,
then (7) yields
1
t
lim inf kz − Γk (t)k = (1 − t) lim inf
z−
ym − ymk+1
k→∞
k→∞
1−t
1−t k
1
2
1
≥ lim 1 −
= .
2 k→∞
k+1
2
In the case when t > 1/2 from (6) and (8) we see that
t
3
1
z−
ym − y −
lim inf kz − Γk (t)k ≥ (1 − t) lim inf
k→∞
k→∞
1−t
1−t k
k+1
1
1
1−t
= t lim inf z −
y − ymk ≥ t > .
k→∞
t
t
2
Hence
lim inf kx − Γk (t)k ≥ lim inf kz − Γk (t)k − ǫ ≥
k→∞
k→∞
and passing to the limit with ǫ → 0, we finally obtain
1
1
lim inf kx − Γk (t)k ≥ = χ(A).
k→∞
2
2
This clearly implies the desired conclusion.
1
−ǫ
2
Let us point out that in general the coefficient 1/2 in Lemma 3.2 cannot be replaced
by any bigger constant. To see this we consider the closed convex hull A of the standard
basis (en ) of the unit vectors in c0 . Given x ∈ c0 we write x = (x(n)), where x(n) ∈ R
for all n ∈ N. Then
(
)
∞
X
A = x ∈ c0 :
x(n) ≤ 1, x(n) ≥ 0, n = 1, 2, . . .
n=1
and it is easy to see that χ(A) = 1.
Let Γ be a curve in A. We will show that there exists x ∈ c0 such that
1
lim inf kx − Γ(t)k ≤ .
t→+∞
2
To this end assume that lim inf t→+∞ kΓ(t)k > 1/2. Then we can find s ≥ 0 such that
inf{kΓ(t)k : t ≥ s} > 1/2. Consequently, for every t ≥ s there exists a unique positive
integer n = n(t) for which (Γ(t))(n) > 1/2. Since n(t) is a continuous function of t we
see that it is constant, i.e. there is m ∈ N such that (Γ(t))(m) > 1/2 for every t ≥ s. It
follows that lim inf t→+∞ kem − Γ(t)k ≤ 1/2.
Lemma 3.3. Let X be a separable Banach space
S and (Xn ) be an ascending sequence of
finite dimensional subspaces of X such that ∞
n=1 Xn is dense in X. Given δ > 0, we
put U1 = {x ∈ X : dist(x, X1 ) < 2δ/3} and
1
1
Un = x ∈ X : dist(x, Xn ) < δ 1 −
, dist(x, Xn−1 ) > δ 1 −
n+2
n
S∞
if n ≥ 2. Then X = k=1 Uk and a nonempty bounded subset A of X satisfies the
condition χ(A) < δ if and only if the set {n ∈ N : Un ∩ A 6= ∅} is finite.
FIXED POINT FREE MAPPINGS WHICH SATISFY A DARBO TYPE CONDITION
11
Proof. Let x ∈ X. If x ∈
/ U1 , then dist(x, X1 ) > δ/2, so the set
1
M = n ∈ N : n ≥ 2, dist(x, Xn−1 ) > δ 1 −
n
is nonempty. It is also finite and we put k = max M . Then
S dist(x, Xk ) ≤ δ(1 − 1/(k + 1))
which shows that x ∈ Uk . We therefore see that X = ∞
k=1 Uk .
Let A be a nonempty bounded subset of X. If χ(A) < δ, then A can be covered with
finitely many balls with radii less than δ. We can assume that their centers are contained
in some subspace Xn . Thus there exists m such that dist(x, Xm ) < δ (1 − 1/(m
S + 1))
for every x ∈ A. This shows that A ∩ Uk = ∅ for all k > m. Conversely, if A ⊂ nk=1 Uk
for some n, then dist(x, Xn ) < δ (1 − 1/(n + 2)) for every x ∈ A. Using the assumption
that A is bounded and the subspace Xn is finite dimensional, we now easily conclude
that χ(A) < δ.
Using Lemma 3.2 and Theorem 1 in [19], one can show that if a weakly compact convex
subset A of a separable Banach space X is not compact, then for every ǫ > 0 there exists
a continuous mapping F : X → A such that [F ]χ ≤ 1/4 and d(F ) > χ(A)/4 − ǫ. Our
next theorem generalizes this result.
Theorem 3.4. Let X be a separable Banach space and let A be a convex weakly compact subset of X which is not compact. Then for every positive δ and ǫ there exists a
continuous mapping F : X → A such that [F ]χ ≤ χ(A)/δ and
1
d(F ) ≥ χ(A) − δ − ǫ.
2
Proof. Let Γ be a simple curve in A constructed in the proof of Lemma 3.2.
S∞We take
an ascending sequence (Xn ) of finite dimensional subspaces of X such that n=1 Xn is
dense in X and δ > 0. Let (Un ) be the corresponding sequence of sets constructed in
Lemma 3.3. We choose an increasing sequence (tn ) of positive numbers such that for
every n ∈ N
1
(9)
kx − Γ(t)k ≥ χ(A) − ǫ
2
whenever x ∈ Xn and t ≥ tn . Given n ∈ N and x ∈ X, we set
µn (x)
φn (x) = P∞
k=1 µk (x)
where µk (x) = dist(x, X \ Uk ). Observe that each x ∈ X belongs to Uk for at most two
values of k. Only for those values µk (x) 6= 0. Moreover, there exist a ball B centered at
x and a set S ⊂ N consisting of at most three numbers such that µk (y) = 0 for all y ∈ B
and k ∈ N \ S. It follows that the formula
!
∞
X
F (x) = Γ
φn (x)tn
n=1
gives a continuous function F : X → A.
Consider a nonempty bounded set C ⊂ X. If χ(C) < δ, then by Lemma 3.3 there
is m ∈ N such that µn (x) = 0 for every x ∈ C and every n > m. This shows that the
set F (C) is compact. If in turn χ(C) ≥ δ, then χ(F (C)) ≤ χ(A) ≤ χ(A)χ(C)/δ. This
shows that [F ]χ ≤ χ(A)/δ.
12
E. MALUTA, S. PRUS, AND J. WOŚKO
If x ∈ X, then x ∈ Un ∪ Un+1 for some n. Consequently,
F (x) = Γ (φn (x)tn + φn+1 (x)tn+1 ) .
There exists y ∈ Xn such that kx − yk < δ (1 − 1/(n + 2)). From (9) we obtain
1
kx − F (x)k ≥ ky − F (x)k − kx − yk > χ(A) − ǫ − δ.
2
The separability assumption can be relaxed in Theorem 3.4. Namely, there is a large
class of Banach spaces X such that for each separable subspace Y of X there exists a
norm-one linear projection P on X for which P (X) is separable and Y ⊂ P (X). This
class contains all reflexive spaces and more generally all weakly compactly determined
spaces (see [6]). Given such space X, we can proceed as in the proof of Theorem 3.4. We
just consider a separable subspace Y containing the curve Γ and find a corresponding
projection P . Then the proof of Theorem 3.4 gives us the mapping F : P (X) → Γ and
we put F1 = F ◦ P . It is easy to see that if A ⊂ P (X), then the Hausdorff measures of
noncompactness of A relative to P (X) and X coincide. Moreover, d(F1 ) = d(F ). We
therefore obtain the following corollary.
Corollary 3.5. The conclusion of Theorem 3.4 holds for any convex weakly compact,
but not compact subset A of a weakly compactly determined Banach space X.
We use results of Banach space theory in the proofs of Theorems 2.3, 3.1, and 3.4.
However, the assumption of completeness of X is not essential in these theorems. Indeed,
if X is not complete, then considering its completion X, we can obtain an appropriate
mapping F defined on X and take its restriction to X. In Theorems 2.3 and 3.4 we deal
with the Hausdorff measure of noncompactness related to the whole space, but it is easy
to see that such measures evaluated with respect to X and X are equal.
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Elisabetta Maluta, Dipartimento di Matematica, Politecnico di Milano, Via Bonardi
9, 20133 Milano MI, Italy
E-mail address: elimal@mate.polimi.it
Stanislaw Prus, Institute of Mathematics, M. Curie-Sklodowska University, 20-031
Lublin, Poland
E-mail address: bsprus@golem.umcs.lublin.pl
Jacek Wośko, Institute of Mathematics, M. Curie-Sklodowska University, 20-031
Lublin, Poland
E-mail address: jwosko@golem.umcs.lublin.pl