cout << "Enter size of array: " << endl;
cin >> size;
cout << "Enter elements: ";
for(i=0;i<size;i++)
{
cin >> array[i];
}
chubbyy.putto 0 Junior Poster in Training
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Jump to Postproblem display the unchange array
i don't see the code for displaying an array. you should use
cout<<for displaying
i don't know what do you mean by the word unchange.you should declare a pointer variable because i think you wanna play with dynamic array.so try …
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Ancient Dragon 5,243 Achieved Level 70 Team Colleague Featured Poster
what's the problem? How is array declared?
Learner010 99 Posting Whiz in Training
problem display the unchange array
i don't see the code for displaying an array. you should use cout<< for displaying
i don't know what do you mean by the word unchange.
you should declare a pointer variable because i think you wanna play with dynamic array.so try this:
int* array;
cout<<"enter size";
cin>>size;
array=new int[size];
here is code for getting input:
for(i=0;i<size;i++)
{
cin>>array[i];
}
and for displaying an array:
for(i=0;i<size;i++)
{
cout<<array[i];
}
instead of code, you provide nothing.
please explain your question.
Ancient Dragon commented: right +14
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