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Block 1
Intersection of Lines
What is to be learned?
• How to find where straight lines meet
(point of intersection)
3x + 2y = 17
2x – 5y = 5
3x + 2y = 17 X5→ 15x + 10y = 85
2x – 5y = 5 X2→ 4x – 10y = 10
Add 19x = 95
x = 5
Consider two lines
simultaneous equations
15 + 2y = 17
y = 1
POI (5 , 1)
(the Elimination Method)
Lines usually written:
y = 5x + 1
y = 3x + 7
Could still use elimination!
→ y – 5x = 1
→ y – 3x = 7
Lines usually written:
y = 5x + 1
y = 3x + 7
So 5x + 1
2x + 1 = 7
2x = 6
x = 3
Point of intersection (3 , 16)
Must
be the
same
y = 5(3) +1 = 16
Known as
y=y tactic= 3x + 7
£y £y
Using y = y
Find the points of intersection, for these
pairs of lines:
1. y = 5x – 3 and y = 2x + 12
2. y = 7x + 8 and y = x +20
3. y = -2x + 8 and y = 2x + 12
4. y = 5x + 3 and y = 24 – 2x
(5,22)
(2,22)
(-1,10)
(3,18)
What is to be learned?
• How to find where straight lines meet
(point of intersection)
y = 2x
5x + 3y = 22
Handy!
y = 2x
5x + 3y = 22
Replace y with 2x
5x + 3 = 22
5x + 6x = 22
11x = 22
x = 2
x = 2
y = 2(2)
= 4
Intersection (2 , 4)
(2x)y
Handy!
substitution
y = 4x + 3
3x + 2y = 17
substitution
y = 4x + 3
3x + 2y = 17
Replace y with 4x + 3
3x + 2 = 17
3x + 8x + 6 = 17
11x + 6 = 17
11x = 11
x = 1
y = 4 (1) +3
= 7
Intersection (1 , 7)
(4x+3)y
substitution
Using Substitution
Find intersections of these lines:
1. x = 8 and
2y + 4x = 42
2. y = 8 and
3y = 2x + 4
3. y = 2x and
2y + 3x = 28
Using Substitution
Find intersections of these lines:
1. x = 8 and
2y + 4x = 42 (8 , 5)
2. y = 8 and
3y = 2x + 4
3. y = 2x and
2y + 3x = 28
Using Substitution
Find intersections of these lines:
1. x = 8 and
2y + 4x = 42 (8 , 5)
2. y = 8 and
3y = 2x + 4 (10 , 8)
3. y = 2x and
2y + 3x = 28
Using Substitution
Find intersections of these lines:
1. x = 8 and
2y + 4x = 42 (8 , 5)
2. y = 8 and
3y = 2x + 4 (10 , 8)
3. y = 2x and
2y + 3x = 28 (4 , 8)
Points of Intersection
Can use
• Simultaneous Equations
• y = y
• Substitution
Depends on way lines are given
Ex 1 y = 5x – 3
y = 3x + 5
Ex 1 y = 5x – 3
y = 3x + 5
y = y
5x – 3 = 3x + 5
2x = 8
x = 4
y = 5(4) – 3 = 17
Intersection (4 , 17)
Ex 2 3x + 2y = 15
2x + 5y = 21
Simultaneous Equations
Ex 3 2x + 3y = 13
y = 2x – 1
Substitute y= 2x – 1 into*
2x + 3(2x – 1) = 13
2x + 6x – 3 = 13
8x = 16
x = 2
y = 2 (2) – 1 = 3
(from second equation)
Intersection (2 , 3)
*
.
You can often rearrange
the equations to use
your favourite tactic

More Related Content

Intersection of lines

  • 2. What is to be learned? • How to find where straight lines meet (point of intersection)
  • 3. 3x + 2y = 17 2x – 5y = 5 3x + 2y = 17 X5→ 15x + 10y = 85 2x – 5y = 5 X2→ 4x – 10y = 10 Add 19x = 95 x = 5 Consider two lines simultaneous equations 15 + 2y = 17 y = 1 POI (5 , 1) (the Elimination Method)
  • 4. Lines usually written: y = 5x + 1 y = 3x + 7 Could still use elimination! → y – 5x = 1 → y – 3x = 7
  • 5. Lines usually written: y = 5x + 1 y = 3x + 7 So 5x + 1 2x + 1 = 7 2x = 6 x = 3 Point of intersection (3 , 16) Must be the same y = 5(3) +1 = 16 Known as y=y tactic= 3x + 7 £y £y
  • 6. Using y = y Find the points of intersection, for these pairs of lines: 1. y = 5x – 3 and y = 2x + 12 2. y = 7x + 8 and y = x +20 3. y = -2x + 8 and y = 2x + 12 4. y = 5x + 3 and y = 24 – 2x (5,22) (2,22) (-1,10) (3,18)
  • 7. What is to be learned? • How to find where straight lines meet (point of intersection)
  • 8. y = 2x 5x + 3y = 22 Handy!
  • 9. y = 2x 5x + 3y = 22 Replace y with 2x 5x + 3 = 22 5x + 6x = 22 11x = 22 x = 2 x = 2 y = 2(2) = 4 Intersection (2 , 4) (2x)y Handy! substitution
  • 10. y = 4x + 3 3x + 2y = 17 substitution
  • 11. y = 4x + 3 3x + 2y = 17 Replace y with 4x + 3 3x + 2 = 17 3x + 8x + 6 = 17 11x + 6 = 17 11x = 11 x = 1 y = 4 (1) +3 = 7 Intersection (1 , 7) (4x+3)y substitution
  • 12. Using Substitution Find intersections of these lines: 1. x = 8 and 2y + 4x = 42 2. y = 8 and 3y = 2x + 4 3. y = 2x and 2y + 3x = 28
  • 13. Using Substitution Find intersections of these lines: 1. x = 8 and 2y + 4x = 42 (8 , 5) 2. y = 8 and 3y = 2x + 4 3. y = 2x and 2y + 3x = 28
  • 14. Using Substitution Find intersections of these lines: 1. x = 8 and 2y + 4x = 42 (8 , 5) 2. y = 8 and 3y = 2x + 4 (10 , 8) 3. y = 2x and 2y + 3x = 28
  • 15. Using Substitution Find intersections of these lines: 1. x = 8 and 2y + 4x = 42 (8 , 5) 2. y = 8 and 3y = 2x + 4 (10 , 8) 3. y = 2x and 2y + 3x = 28 (4 , 8)
  • 16. Points of Intersection Can use • Simultaneous Equations • y = y • Substitution Depends on way lines are given
  • 17. Ex 1 y = 5x – 3 y = 3x + 5
  • 18. Ex 1 y = 5x – 3 y = 3x + 5 y = y 5x – 3 = 3x + 5 2x = 8 x = 4 y = 5(4) – 3 = 17 Intersection (4 , 17)
  • 19. Ex 2 3x + 2y = 15 2x + 5y = 21 Simultaneous Equations
  • 20. Ex 3 2x + 3y = 13 y = 2x – 1 Substitute y= 2x – 1 into* 2x + 3(2x – 1) = 13 2x + 6x – 3 = 13 8x = 16 x = 2 y = 2 (2) – 1 = 3 (from second equation) Intersection (2 , 3) *
  • 21. . You can often rearrange the equations to use your favourite tactic