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2

The following formulae may be helpful in answering the questions. The symbols given
are the ones commonly used.

Rumus-rumus berikut boleh membantu anda menjawab soalan. Simbol-simbol yang
diberi adalah yang biasa digunakan.
                                    ALGEBRA

         − b ± b 2 − 4ac                        log a b =
                                                          log c b
1    x=                                    8
               2a                                         log c a
2     a × a = a m+n
       m     n                             9    Tn = a + (n – 1)d

3    a m ÷ a n = a m-n
                                           10            n
                                                Sn =       [ 2a + (n – 1) d ]
4    ( a m ) n = a mn                                    2

5    loga mn = loga m + loga n             11   Tn = ar n−1

6           m                              12        a ( r n − 1)   a (1 − r n )
     loga     = loga m – loga n                 Sn =              =              ,r≠1
            n                                            r −1          1− r
7   loga mn = n loga m                     13           a
                                                S∞ =         , r <1
                                                     1−r




                                  CALCULUS / KALKULUS

1              dy   dv  du                 4    Area under a curve
    y = uv,       =u +v                         Luas di bawah lengkung
               dx   dx  dx
                                                    b

               du    dv
                                                =   ∫y    dx or (atau)
2            v    −u                                a
       u dy
     y= ,   = dx 2 dx
       v dx       v                                 b
                                                =   ∫ x dy
                                                    a

                                           5    Volume generated / Isipadu janaan
     dy dy du
3      =  ×                                         b
     dx du dx
                                                = ∫ πy 2 dx or ( atau)
                                                    a
                                                    b
                                                = ∫ πx 2 dy
                                                    a
3


                                           STATISTICS / STATISTIK

1
     x=
             ∑x                                               7
                                                                       I=
                                                                             ∑W I     i i
             N                                                               ∑W        i

2            ∑ fx                                             8        n              n!
     x=                                                                    Pr =
             ∑f                                                                   ( n − r )!

3
     σ=
              ∑ ( x − x)   2

                               =
                                       ∑x   2

                                                −x
                                                     2
                                                              9        n
                                                                           Cr =
                                                                                       n!
                                                                                  ( n − r )! r!
                    N                  N

4
     σ=
              ∑ f ( x − x)     2

                                   =
                                       ∑ fx     2

                                                    −x
                                                         2
                                                              10      P(A∪B) = P(A) + P(B) – P(A∩B)

                 ∑f                    ∑f                     11      P(X = r) = n C r p r q n − r , p + q = 1

5             1 N −F                                        12      Mean / Min , µ = np
        m=L+ 2       C
              f      
                  m                                         13      σ = npq

6            Q1                                               14             X −µ
        I=      × 100                                                 Z=
             Q0                                                                   σ




                                           GEOMETRY / GEOMETRI

1   Distance / Jarak                                4    Area of triangle / Luas segitiga
         ( x2 − x1 ) + ( y2 − y1 )
                    2                  2                  1
    =                                                    = ( x1 y 2 + x 2 y 3 + x3 y1 ) − ( x 2 y1 + x3 y 2 + x1 y 3 )
                                                          2

2   Midpoint / Titik tengah                         5        r = x2 + y 2
              x + x 2 y1 + y 2 
    (x, y) =  1      ,         
              2          2                             ∧        xi + y j
                                                    6
                                                         r=
                                                                  x2 + y 2

3   A point dividing a segment of a line
    Titik yang membahagi suatu tembereng garis
              nx + mx 2 ny1 + my 2 
    (x, y) =  1        ,           
              m+n         m+n 
4


                          TRIGONOMETRY / TRIGONOMETRI

1   Arc length, s = r θ             8        sin (A ± B) = sin A cos B ± cos A sin B
    Panjang lengkok, s = j θ                 sin (A ± B) = sin A kos B ± kos A sin B


                        1
2   Area of sector, A = r 2 θ       9        cos (A ± B) = cos A cos B  sin A sin B
                        2
                      1 2
    Luas sektor, L = j θ                     kos (A ± B) = kos A kos B  sin A sin B
                      2

3   sin 2 A + cos 2 A =1            10       tan (A ± B ) =    tan A ± tan B
    sin 2 A + kos 2 A =1
                                                              1  tan A tan B

                                    11                    2 tan A
4   sec 2 A = 1 + tan 2 A                    tan 2 A =
                                                         1 − tan 2 A
    sek 2 A = 1 + tan 2 A


5   cosec 2 A = 1 + cot 2 A         12         a
                                                  =
                                                     b
                                                         =
                                                             c
                                             sin A sin B   sin C
    kosek 2 A = 1 + kot 2 A


6   sin 2A = 2 sin A cos A          13       a 2 = b 2 + c 2 – 2bc cos A
    sin 2A = 2 sin A kos A
                                             a 2 = b 2 + c 2 – 2bc kos A


7   cos 2A = cos2 A – sin2 A        14       Area of triangle / Luas segitiga
           = 2 cos 2 A – 1                   =
                                               1
                                                 ab sin C
           = 1 – 2 sin 2 A                     2

    kos 2A = kos2 A – sin2 A
           = 2 kos 2 A – 1
           = 1 – 2 sin 2 A

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2 senarai rumus add maths k1 trial spm sbp 2010

  • 1. 2 The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. Rumus-rumus berikut boleh membantu anda menjawab soalan. Simbol-simbol yang diberi adalah yang biasa digunakan. ALGEBRA − b ± b 2 − 4ac log a b = log c b 1 x= 8 2a log c a 2 a × a = a m+n m n 9 Tn = a + (n – 1)d 3 a m ÷ a n = a m-n 10 n Sn = [ 2a + (n – 1) d ] 4 ( a m ) n = a mn 2 5 loga mn = loga m + loga n 11 Tn = ar n−1 6 m 12 a ( r n − 1) a (1 − r n ) loga = loga m – loga n Sn = = ,r≠1 n r −1 1− r 7 loga mn = n loga m 13 a S∞ = , r <1 1−r CALCULUS / KALKULUS 1 dy dv du 4 Area under a curve y = uv, =u +v Luas di bawah lengkung dx dx dx b du dv = ∫y dx or (atau) 2 v −u a u dy y= , = dx 2 dx v dx v b = ∫ x dy a 5 Volume generated / Isipadu janaan dy dy du 3 = × b dx du dx = ∫ πy 2 dx or ( atau) a b = ∫ πx 2 dy a
  • 2. 3 STATISTICS / STATISTIK 1 x= ∑x 7 I= ∑W I i i N ∑W i 2 ∑ fx 8 n n! x= Pr = ∑f ( n − r )! 3 σ= ∑ ( x − x) 2 = ∑x 2 −x 2 9 n Cr = n! ( n − r )! r! N N 4 σ= ∑ f ( x − x) 2 = ∑ fx 2 −x 2 10 P(A∪B) = P(A) + P(B) – P(A∩B) ∑f ∑f 11 P(X = r) = n C r p r q n − r , p + q = 1 5  1 N −F  12 Mean / Min , µ = np m=L+ 2 C  f   m  13 σ = npq 6 Q1 14 X −µ I= × 100 Z= Q0 σ GEOMETRY / GEOMETRI 1 Distance / Jarak 4 Area of triangle / Luas segitiga ( x2 − x1 ) + ( y2 − y1 ) 2 2 1 = = ( x1 y 2 + x 2 y 3 + x3 y1 ) − ( x 2 y1 + x3 y 2 + x1 y 3 ) 2 2 Midpoint / Titik tengah 5 r = x2 + y 2  x + x 2 y1 + y 2  (x, y) =  1 ,   2 2  ∧ xi + y j 6 r= x2 + y 2 3 A point dividing a segment of a line Titik yang membahagi suatu tembereng garis  nx + mx 2 ny1 + my 2  (x, y) =  1 ,   m+n m+n 
  • 3. 4 TRIGONOMETRY / TRIGONOMETRI 1 Arc length, s = r θ 8 sin (A ± B) = sin A cos B ± cos A sin B Panjang lengkok, s = j θ sin (A ± B) = sin A kos B ± kos A sin B 1 2 Area of sector, A = r 2 θ 9 cos (A ± B) = cos A cos B  sin A sin B 2 1 2 Luas sektor, L = j θ kos (A ± B) = kos A kos B  sin A sin B 2 3 sin 2 A + cos 2 A =1 10 tan (A ± B ) = tan A ± tan B sin 2 A + kos 2 A =1 1  tan A tan B 11 2 tan A 4 sec 2 A = 1 + tan 2 A tan 2 A = 1 − tan 2 A sek 2 A = 1 + tan 2 A 5 cosec 2 A = 1 + cot 2 A 12 a = b = c sin A sin B sin C kosek 2 A = 1 + kot 2 A 6 sin 2A = 2 sin A cos A 13 a 2 = b 2 + c 2 – 2bc cos A sin 2A = 2 sin A kos A a 2 = b 2 + c 2 – 2bc kos A 7 cos 2A = cos2 A – sin2 A 14 Area of triangle / Luas segitiga = 2 cos 2 A – 1 = 1 ab sin C = 1 – 2 sin 2 A 2 kos 2A = kos2 A – sin2 A = 2 kos 2 A – 1 = 1 – 2 sin 2 A