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praktikum hukum lavoisier

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Adinda Melinda Ceria Adjie
Adinda Melinda Ceria Adjie

Lavoisier Law ,Law of mass conservation. “The total amount of matter of the reaction compounds remains constant”

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LAVOISIER LAW CHEMICAL PRACTICE REPORT By : Adinda Melinda C.A Amalia Prasiwi Lazulfa Inda Lestari Nurul Fatimah Rifa Abriyanti Tanza Lona Trista X-8 SMA NEGERI 2 CIMAHI 2011
Experiment 1 I. Title : Lavoisier Law II. Goal : To proof that the mass of the substance before and after reaction is the same. III. Theory : Based on Lavoisier Law ,Law of mass conservation. “The total amount of matter of the reaction compounds remains constant” IV. Materials and Equipment : a. Y tube b. O’hauss Balance c. Pippet d. Pb(NO3)2 liquid e. KI liquid V. Procedure : a. Measure the Y tube into O’hauss Balance in empty condition. b. Input ten drops of Pb(NO3)2 liquid to the one part of the Y tube. c. Input ten drops of KI liquid on the other parts of the Y tube . d. Measure again the Y tube wich is contains both of the liquid using O’hauss Balance. e. Mix both of the liquids in one side of Y tube. f. Again, measure the Y tube wich is contains the result of reaction. VI. Observation : Mass before reaction Mass after reaction 32,05 gr 32,05 gr VII. Question : 1. Write down the chemical equation from the experiment ! 2. From the experiment ,explain the Lavoisier law ! Answer : 1. 2KI + Pb(NO3)2 PbI2 + 2KNO3 2. Lavoisier states that the total amount of matter of the reaction compounds remains constant.
VIII. Conclution : From this experiment we can proved the truth of the Lavoisier law, law of Mass Conservation. “mass of the substance before and after reaction is the same” Experiment 2 I. Title : Identification C,H,O II. Goal : To identify C,H,O by evaporation III. Theory : The existence of the elements carbon and hydrogen in organic samples, more certain can be shown through chemical means, namely by the combustion test. IV. Materials and Equipment : a. spirtus b. matches c. 2 reaction tubes d. pippet e. spatula f. gas pipeline g. Clamp h. Sugar (C12H22O11) i. Ca(OH)2 liquid j. CuO powder V. Procedure : a. Pour a half spatula of CuO into the reaction tube. b. Pour a spatula of sugar into the same reaction tube. c. Mix both of the materials. d. Input the Ca(OH)2 liquid into the second reaction tube. e. Set all equipments based on the picture :
VI. Question : 1. Write down the chemical formula of burning sugar and functions of CuO ! 2. Why does appears lime water become cloudly ? 3. Make chemical equation for number two ! 4. What happened with cobalt paper after tested ? 5. Write the chemical equation for number four ! Answer : 1. C12H22 O11 (S) + CuO(S) CO2(g) + H2O(g) + C(s) . Function of CuO is as an oxidant 2. Because the reaction produce CO2 ,then it reacts with limewater (Ca(OH)2) .So,the colour of lime water become transparent and cloudly. 3. Ca(OH)2(aq) + CO2 (g) CaCO3(s) + H2O(g) 4. The colour of cobalt paper turns from blue to pink. 5. COCl2(s) + 6H2O(g) COCl.6H2O VII. Conclution : From this experiment we can prove that in the sugar compounds there are elements C (carbon) ,H (Hydrogen),O (Oxygen). The existence of elements of C can be evidenced by color changes that occur in the limewater solution becomes turbid. While the elements of H can be proved by using cobalt blue paper. Compounds having these elements is an Organic Compounds.
Experiment 3 I. Title : Redox reaction II.Goal : To prove the redox reaction between Zn and CuSO4. III.Theory : There are three concepts used to explain the definition of redox reaction. Those three concepts are the release and uptake of oxygen atom,the electrons transfer,and the change in oxidation number. IV.Materials and Equipment : a. Test tube b. A piece of Zn (zinc) c. CuSO4 Liquid V. Procedure : a. Pour the CuSO4 liquid into the test tube. b. Put Zn into the same test tube. c. Wait for some hours. d. Observe that occur on Zn and CuSO4. VI. Observation : Subtance Before reaction After reaction Zn  Had silver colour  Solid  Dissolved  The colour changed to black.  Changed to ZnSO4 CuSO4  Had blue colour  Liquid  React with Zn produce ZnSO4  Cu be a red black sediment.  Had transparent colour. VII. Question : 1. Determine the oxidation number for each substance ! 2. Determine the oxidizers and reducers !
Answer : 1. Zn + CuSO4 ZnSO4 + Cu Reactant  Zn = 0  S in SO4 -2 = (1x S oxydation number) + (4x O oxydation number) -2 = S + (-8) -2+8 = S S = 6  Cu in CuSo4 = (1 x Cu) + (1 + S) + (4x O ) 0 = Cu + 6 + (- 8) Cu =2 Product  Zn in ZnSO4 = (1xZn) + (1xS) + (4xO) 0 = Zn + 6 + (-8) Zn = 2  Cu = 0 2. Reducer : Zn Oxidator : Cu VIII. Conclution : From this experiment we can prove that redox reaction happen between Zn and CuSO4 .With Zn as Reducer and CuSO4 as oxidator.

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praktikum hukum lavoisier

  • 1. LAVOISIER LAW CHEMICAL PRACTICE REPORT By : Adinda Melinda C.A Amalia Prasiwi Lazulfa Inda Lestari Nurul Fatimah Rifa Abriyanti Tanza Lona Trista X-8 SMA NEGERI 2 CIMAHI 2011
  • 2. Experiment 1 I. Title : Lavoisier Law II. Goal : To proof that the mass of the substance before and after reaction is the same. III. Theory : Based on Lavoisier Law ,Law of mass conservation. “The total amount of matter of the reaction compounds remains constant” IV. Materials and Equipment : a. Y tube b. O’hauss Balance c. Pippet d. Pb(NO3)2 liquid e. KI liquid V. Procedure : a. Measure the Y tube into O’hauss Balance in empty condition. b. Input ten drops of Pb(NO3)2 liquid to the one part of the Y tube. c. Input ten drops of KI liquid on the other parts of the Y tube . d. Measure again the Y tube wich is contains both of the liquid using O’hauss Balance. e. Mix both of the liquids in one side of Y tube. f. Again, measure the Y tube wich is contains the result of reaction. VI. Observation : Mass before reaction Mass after reaction 32,05 gr 32,05 gr VII. Question : 1. Write down the chemical equation from the experiment ! 2. From the experiment ,explain the Lavoisier law ! Answer : 1. 2KI + Pb(NO3)2 PbI2 + 2KNO3 2. Lavoisier states that the total amount of matter of the reaction compounds remains constant.
  • 3. VIII. Conclution : From this experiment we can proved the truth of the Lavoisier law, law of Mass Conservation. “mass of the substance before and after reaction is the same” Experiment 2 I. Title : Identification C,H,O II. Goal : To identify C,H,O by evaporation III. Theory : The existence of the elements carbon and hydrogen in organic samples, more certain can be shown through chemical means, namely by the combustion test. IV. Materials and Equipment : a. spirtus b. matches c. 2 reaction tubes d. pippet e. spatula f. gas pipeline g. Clamp h. Sugar (C12H22O11) i. Ca(OH)2 liquid j. CuO powder V. Procedure : a. Pour a half spatula of CuO into the reaction tube. b. Pour a spatula of sugar into the same reaction tube. c. Mix both of the materials. d. Input the Ca(OH)2 liquid into the second reaction tube. e. Set all equipments based on the picture :
  • 4. VI. Question : 1. Write down the chemical formula of burning sugar and functions of CuO ! 2. Why does appears lime water become cloudly ? 3. Make chemical equation for number two ! 4. What happened with cobalt paper after tested ? 5. Write the chemical equation for number four ! Answer : 1. C12H22 O11 (S) + CuO(S) CO2(g) + H2O(g) + C(s) . Function of CuO is as an oxidant 2. Because the reaction produce CO2 ,then it reacts with limewater (Ca(OH)2) .So,the colour of lime water become transparent and cloudly. 3. Ca(OH)2(aq) + CO2 (g) CaCO3(s) + H2O(g) 4. The colour of cobalt paper turns from blue to pink. 5. COCl2(s) + 6H2O(g) COCl.6H2O VII. Conclution : From this experiment we can prove that in the sugar compounds there are elements C (carbon) ,H (Hydrogen),O (Oxygen). The existence of elements of C can be evidenced by color changes that occur in the limewater solution becomes turbid. While the elements of H can be proved by using cobalt blue paper. Compounds having these elements is an Organic Compounds.
  • 5. Experiment 3 I. Title : Redox reaction II.Goal : To prove the redox reaction between Zn and CuSO4. III.Theory : There are three concepts used to explain the definition of redox reaction. Those three concepts are the release and uptake of oxygen atom,the electrons transfer,and the change in oxidation number. IV.Materials and Equipment : a. Test tube b. A piece of Zn (zinc) c. CuSO4 Liquid V. Procedure : a. Pour the CuSO4 liquid into the test tube. b. Put Zn into the same test tube. c. Wait for some hours. d. Observe that occur on Zn and CuSO4. VI. Observation : Subtance Before reaction After reaction Zn  Had silver colour  Solid  Dissolved  The colour changed to black.  Changed to ZnSO4 CuSO4  Had blue colour  Liquid  React with Zn produce ZnSO4  Cu be a red black sediment.  Had transparent colour. VII. Question : 1. Determine the oxidation number for each substance ! 2. Determine the oxidizers and reducers !
  • 6. Answer : 1. Zn + CuSO4 ZnSO4 + Cu Reactant  Zn = 0  S in SO4 -2 = (1x S oxydation number) + (4x O oxydation number) -2 = S + (-8) -2+8 = S S = 6  Cu in CuSo4 = (1 x Cu) + (1 + S) + (4x O ) 0 = Cu + 6 + (- 8) Cu =2 Product  Zn in ZnSO4 = (1xZn) + (1xS) + (4xO) 0 = Zn + 6 + (-8) Zn = 2  Cu = 0 2. Reducer : Zn Oxidator : Cu VIII. Conclution : From this experiment we can prove that redox reaction happen between Zn and CuSO4 .With Zn as Reducer and CuSO4 as oxidator.