Module 1

1
Answer all questions.
1.
In Diagram 1, the function f maps set A to set B and the function g maps set B to set C.
Determine
(a) f (3 )
(b) g(-1)
(c) gf (3)
[ 3 marks
]
Answer : (a) ……………………..
(b) ……………………...
(c)....................................
2. Given function f : x → 3 − 4x and function g : x → x2
− 1, find
(a) f −1
,
(b) the value of f −1
g(3).
[ 3 marks
]
Answer : (a) ……………………..
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3
2
3
1
For examiner’s
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f g
Diagram 1
Set A Set B Set C
3
-1 6

2
(b) ……………………...
3 Given the function f (x) = 4x, 0≠x and the composite function f g(x) =
x
16−
. Find
(a) g(x),
(b) the value of x when g(x) = 8.
Answer : .........…………………
4 Solve the quadratic equation ( ) ( )( )3252 +−=− xxxx . Give your answer correct to
four significant figures.
[ 3 marks ]
Answer : .........…………………
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3
4
3
3
[3 marks]

3
5 (a) Given x =
4
2
− y
, find the range of x if y > 10.
(b) Find the range of x if x2
− 2x ≤ 3. [4 marks]
Answer : .................................
___________________________________________________________________________
6 Diagram below shows the graph of a quadratic function )(xfy = . The straight line
9−=y is a tangent to the curve )(xfy = .
a) Write the equation of the axis of symmetry of the curve.
b) Express )(xf in form of qpx ++ 2
)( , where p and q are constants.
[ 3 marks ]
Answer : (a) ……........................
(b) ……........................
7 Solve the equation 324x
= 48x + 6
3
6
For examiner’s
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For examiner’s
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)(xfy =
0 1 7
y
y = -9
x
Diagram 1

4
[3 marks]
Answer : ..................................
8. Given log5 3 = 0.683 and log5 7 = 1.209. Calculate
(i) log5 1.4,
(ii) log7 75.
[ 4 marks]
Answer : ...................................
9. Solve the equation log x 16 − log x 2 = 3. [3
marks]
Answer : ......................................
10. The first terms of the series are 2, x , 8. Find the value of x such that the series is a
3
7
3
9
4
8
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5
(a) an arithmetic progression,
(b) a geometric progression. [2 marks ]
Answer : ....……………...………..
11. The sum of the first n terms of an arithmetic progression is given by .133 2
nnSn +=
Find
(a) the ninth term,
(b) the sum of the next 20 terms after the 9th
terms.
[3 marks]
Answer: a)…...…………..….......
b) ....................................
12. Given that
1
0.166666666.....
p
=
3
8
2
10
4
11
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examiner’s
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6
0.1 ............a b= + + + [ 3 marks
]
Find the values of a and b. Hence, find the value of p.
Answer: a =...….… b =….......
p = ........................
___________________________________________________________________________
13. Diagram 2 shows a linear graph of
x
y
against x2
x
y
Given that
x
y
= hx2
+ k, where k and h are contants.
Calculate the value of h and k. [3 marks]
Answer : h = ………………..…….
k = ……………….....…...
(4,1)
(1,-5)
x2
●
●
3
13
4
12
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DIAGRAM 2

7
14. The equation of a straight line PQ is
3
x
+
2
y
= 1. Find the equation of a straight
line that is parallel to PQ and passes through the point (−6 , 3). [3
marks]
Answer : .…………………
15 Given u = 





9
7
dan v = 




 −
3
1p
, find the possible values of p for each of the
following
case:
(a) u and v are parallel, [2 marks]
(b) vu = . [2
marks]
Answer : a)…………………..
b) ………………………
4
15
3
14

8
16 P
The diagram above shows
→
OR = r,
→
OS = s,
→
OP and
→
PQ are drawn in the square
grid.
Express in terms of r and s.
(i)
→
OP
(ii) PQ
uuur
.
[ 3 marks ]
Answer: a) OP
uuur
= …….…………...
b) PQ
uuur
=...………………..
___________________________________________________________________________
17. Solve the equation 3 cos2
θ + sin 2θ = 0 for 00
3600 ≤≤ θ . [ 4 marks ]
R S
Q
r s
O
4
16
4
17
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3
16

9
Answer: …...…………..….......
18.
Diagram above shows a length of wire in the form of sector OPQ, centre O.
The length of the wire is 100 cm. Given the arc length PQ is 20 cm, find
(a) the angle θ in radian, [2 marks]
(b) area of the sector OPQ. [2 marks]
Answer: a)……………………
b) …………………
___________________________________________________________________________
19. Find the equation of the tangent to the curve 3
)5(
5
−
=
x
y at the point (3, 4).
[2 marks]
Answer:………………………
2
19
4
18
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QO
θ

10
20. A roll of wire of length 60 cm is bent into the shape of a circle. When above the
wire is heated, its length increases at a rate of 0.1 cms−1
. (Use π = 3.142)
(i) Calculate the rate of change of radius of the circle. [2 marks]
(ii) Hence, calculate the radius of the circle after 4 seconds. [2 marks]
Answer: …...…………..….......
___________________________________________________________________________
21. Given
4
0
( )f x∫ dx = 5 and
3
1
( )g x∫ dx = 6.
Find the value
(a)
4 1
0 3
2 ( ) ( )f x dx g x dx+∫ ∫ , [1 marks]
(b) k if
3
1
[ ( ) ]g x k x dx−∫ =14. [2 marks]
Answer: a) ……………………..
k =.……………..………
22. A chess club has 10 members of whom 6 are men and 4 are women. A team of 4
members is selected to play in a match. Find the number of different ways of
selecting the team if
(a) all the players are to be of the same gender,
(b) there must be an equal number of men and women.
[3 marks]
5
20
3
21
3
22
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11
Answer: p = …………………….
.
23. (a) Given that the mean for four positive integer is 9. When a number y is added to the
four positive integer, the mean becomes 10. Find the value of y.
[2 marks]
(b) Find the standard deviation for the set of numbers 5, 6, 6, 4, 7. [3 marks]
Answer: …a)...…………..….......
b) ...............................
___________________________________________________________________________
24. Hanif , Zaki and Fauzi will be taking a driving test. The probabilities that Hanif ,
Zaki and Fauzi will pass the test are
1 1
,
2 3
and
1
4
respectively. Calculate the
probability that
(a) only Hanif will pass the test
(b) at least one of them will pass the test.
[ 3 marks ]
Answer: ……………………………
For examiner’s
use only
3
24
5
23

12
25. Diagram below shows a standard normal distribution graph.
Given that the area of shaded region in the diagram is 0.7828 , calculate the value of k.
[ 2 marks ]
Answer: …...…………..….......
END OF QUESTION PAPER
2
25
For examiner’s
use only
-k k z

13
JAWAPAN
1 (a) −1 (b) 6 (c) 6 13 h = 2 , k = −7
2
(a) f −1
=
3
4
x−
(b)
5
4
−
14 3y = − 2x − 3
3
(a) g(x) = 0,
4
≠
−
x
x
(b)
2
1
−=x
15
(a)
3
10
(b) −10, 12
4 3.562 , -0.5616 16 (b)(i) 3r + 2s (ii) − r − 3s
5. (a) x < − 3 (b) −1 ≤ x ≤ 3 17 90°, 123° 41’, 270°, 303° 41’
6 a) 4=x
b) 9)4()( 2
−−= xxf 18
(a)
2
1
(b) 400
7 x = 3 19 15x + 16y −109 = 0
8 ( i) 0.209 (ii) 2.219 20 ( i) 0.01591 cms−1
(ii) 9.612
9 x = 4 21 (a) 4 (b) k = −2
10 a) 5 b) 4 22 14 553
11 (a) 64 ( b) 2540 23 (a ) 14 (b) 1.020
12 a = 0.06 , b = 0.006 , p = 6 24 (a) 9/35 ( b) 5/6
25 k = 1.234

Module 1

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