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Finding the Vertex of a Parabola a step-by-step guide to finding the vertex form of a parabolic function by completing the square
Example 1: To find the vertex of f(x)=x 2 -4x+3 Completing the Square if the coefficient of x 2  is 1.
Example 1: To find the vertex of f(x)=x 2 -4x+3 f(x)=(x 2 -4x  )+3 Separate the x-terms Completing the Square if the coefficient of x 2  is 1.
Example 1:  Continued To find the vertex of f(x)=x 2 -4x+3 f(x)=(x 2 -4 x  )+3 Square half of the coefficient of x (  ) -4 2 2 =4 __
Example 1:  Continued To find the vertex of f(x)=x 2 -4x+3 f(x)=(x 2 -4x  )+3 -4 2 (  ) 2 = 4 f(x)=(x 2 -4x  + 4 )+3 -4 Add this constant inside the parentheses, and subtract it on the outside
Example 1:  Continued Now you are ready to Complete the Square! f(x)=(x 2 -4x + 4)+3-4
Example 1:  Continued Now you are ready to Complete the Square! f(x)=( x 2 -4x + 4 )+3-4 The expression in the parentheses is a perfect square trinomial
Example 1:  Continued Now you are ready to Complete the Square! f(x)=( x 2 -4x + 4 )+3-4 Factor it! f(x)=( x-2 )( x -2 )+3-4
Example 1:  Continued Now you are ready to Complete the Square! f(x)=(x 2 -4x + 4)+3-4 Simplify the right side f(x)=( x-2 )( x -2 )+3-4 f(x)=( x-2 ) 2 -1
Example 1:  Continued The result is now in vertex form:  f(x)=(x-h) 2 +k where (h,k) is the vertex f(x)=(x-2) 2 -1
Example 1:  Continued The result is now in vertex form:  Subtraction is like  adding the opposite f(x)=(x-2) 2  + ( - 1) f(x)=(x-h) 2 +k where (h,k) is the vertex f(x)=(x-2) 2 - 1
Example 1:  Continued The result is now in vertex form:  f(x)=(x- 2 ) 2  +( -1 ) f(x)=(x- h ) 2 + k where (h,k) is the vertex f(x)=(x-2) 2 -1 For our function, h=2 and k=-1
Example 1:  Continued The result is now in vertex form:  f(x)=(x-2) 2  +(-1) f(x)=(x-h) 2 +k where ( h , k ) is the vertex f(x)=(x-2) 2 -1 For our function, h=2 and k=-1 Therefore, the vertex is ( 2 ,  -1 )
Example 1:  Completed Here is the graph of  f(x)=x 2 -4x+3 Vertex is (2, -1)
Example 2: To find the vertex of f(x)=-2x 2 -2x+1 Completing the Square if the coefficient of x 2  is not 1.
Example 2:  Continued To find the vertex of f(x)=-2x 2 -2x+1 f(x)=(-2x 2 -2 x  )+1 Separate the x-terms
Example 2:  Continued To find the vertex of f(x)=-2x 2 -2x+1 f(x)=( -2 x 2 -2 x  )+1 Factor out the  coefficient of x 2 f(x)= -2 (x 2 + x  )+1
Example 2:  Continued To find the vertex of f(x)=-2x 2 -2x+1 f(x)=(-2x 2 -2 x  )+1 f(x)= -2 (x 2 + 1 x  )+1 Square half of the coefficient of x (  ) 1 2 = __ 2 __ 4 1
Example 2:  Continued To find the vertex of f(x)=-2x 2 -2x+1 __ f(x)=(-2x 2 -2 x  )+1 f(x)=-2(x 2 +1x  )+1 (  ) 1 2 = 2 f(x)= -2(x 2 +x+  )+1 Add this constant  inside the parentheses __ 4 1 __ 4 1
Example 2:  Continued To find the vertex of f(x)=-2x 2 -2x+1 __ f(x)=(-2x 2 -2 x  )+1 f(x)=-2(x 2 +1x  )+1 (  ) 1 2 = 2 f(x)=   -2 (x 2 + x+  )+1 Notice we have really added  -2 (  ) to the  equation __ 4 1 __ 4 1 __ 4 1
Example 2:  Continued To find the vertex of f(x)=-2x 2 -2x+1 __ f(x)=(-2x 2 -2 x  )+1 f(x)=-2(x 2 +1x  )+1 (  ) 1 2 = 2 f(x)=   -2 (x 2 + x+  )+1 -( -2 )(  ) Therefore, subtract  -2 (  )  to maintain the same equation __ 4 1 __ 4 1 __ 4 1 __ 4 1
Example 2:  Continued To find the vertex of f(x)=-2x 2 -2x+1 __ f(x)=(-2x 2 -2 x  )+1 f(x)=-2(x 2 +1x  )+1 (  ) 1 2 = 2 f(x)= -2(x 2 +x+  )+ 1-(-2)(  ) Simplify f(x)= -2(x 2 +x+  )+ __ 4 1 __ 4 1 __ 4 1 __ 4 1 __ 2 3
Example 2:  Continued Now you are ready to Complete the Square! 3 f(x)= -2(x 2 +x+  )+ __ 4 1 __ 2
Example 2:  Continued Now you are ready to Complete the Square! 3 f(x)= -2( x 2 +x+  )+ __ 4 1 __ 2 The expression in the parentheses is a perfect square trinomial
Example 2:  Continued Now you are ready to Complete the Square! 3 f(x)= -2( x+  )( x +   )+ f(x)= -2( x 2 +x+   )+ __ 4 1 __ 2 Factor it! __ 2 1 __ 2 1 __ 2 3
Example 2:  Continued Now you are ready to Complete the Square! 3 Simplify the right side f(x)= -2( x+   )( x +   )+ f(x)=-2 ( x+   ) 2  + f(x)= -2(x 2 +x+  )+ __ 4 1 __ 2 __ 2 1 __ 2 1 __ 2 3 __ 2 3 __ 2 1
Example 2:  Continued The result is now in vertex form:  f(x)=a(x-h) 2 +k where (h,k) is the vertex f(x)=-2 (x+  ) 2   + __ 2 3 __ 2 1
Example 2:  Continued The result is now in vertex form:  f(x)=a(x-h) 2 +k where (h,k) is the vertex f(x)=-2 (x -   ) 2   + Change addition to  subtracting the opposite f(x)=-2 (x +   ) 2   + __ 2 3 __ 2 - 1  __ 2 3 __ 2 1
Example 2:  Continued The result is now in vertex form:  f(x)=a(x- h ) 2 + k where (h,k) is the vertex f(x)=-2 (x-  ) 2   + For our function, h=  and k= f(x)=-2 (x+  ) 2   + __ 2 3 __ 2 -1  __ 2 3 __ 2 -1  __ 2 3 __ 2 1
Example 2:  Continued The result is now in vertex form:  f(x)=a(x-h) 2 +k where ( h , k ) is the vertex f(x)=-2 (x-  ) 2   + For our function, h=  and k= f(x)=-2 (x+  ) 2   + Therefore, the vertex is (   ,  ) __ 2 3 __ 2 -1  __ 2 3 __ 2 -1  __ 2 3 __ 2 1 __ 2 -1  __ 2 3
Example 2:  Completed Here is the graph of  f(x)= -2x 2 -2x+1 Vertex is (   ,  ) __ 2 -1  __ 2 3

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Vertex

  • 1. Finding the Vertex of a Parabola a step-by-step guide to finding the vertex form of a parabolic function by completing the square
  • 2. Example 1: To find the vertex of f(x)=x 2 -4x+3 Completing the Square if the coefficient of x 2 is 1.
  • 3. Example 1: To find the vertex of f(x)=x 2 -4x+3 f(x)=(x 2 -4x )+3 Separate the x-terms Completing the Square if the coefficient of x 2 is 1.
  • 4. Example 1: Continued To find the vertex of f(x)=x 2 -4x+3 f(x)=(x 2 -4 x )+3 Square half of the coefficient of x ( ) -4 2 2 =4 __
  • 5. Example 1: Continued To find the vertex of f(x)=x 2 -4x+3 f(x)=(x 2 -4x )+3 -4 2 ( ) 2 = 4 f(x)=(x 2 -4x + 4 )+3 -4 Add this constant inside the parentheses, and subtract it on the outside
  • 6. Example 1: Continued Now you are ready to Complete the Square! f(x)=(x 2 -4x + 4)+3-4
  • 7. Example 1: Continued Now you are ready to Complete the Square! f(x)=( x 2 -4x + 4 )+3-4 The expression in the parentheses is a perfect square trinomial
  • 8. Example 1: Continued Now you are ready to Complete the Square! f(x)=( x 2 -4x + 4 )+3-4 Factor it! f(x)=( x-2 )( x -2 )+3-4
  • 9. Example 1: Continued Now you are ready to Complete the Square! f(x)=(x 2 -4x + 4)+3-4 Simplify the right side f(x)=( x-2 )( x -2 )+3-4 f(x)=( x-2 ) 2 -1
  • 10. Example 1: Continued The result is now in vertex form: f(x)=(x-h) 2 +k where (h,k) is the vertex f(x)=(x-2) 2 -1
  • 11. Example 1: Continued The result is now in vertex form: Subtraction is like adding the opposite f(x)=(x-2) 2 + ( - 1) f(x)=(x-h) 2 +k where (h,k) is the vertex f(x)=(x-2) 2 - 1
  • 12. Example 1: Continued The result is now in vertex form: f(x)=(x- 2 ) 2 +( -1 ) f(x)=(x- h ) 2 + k where (h,k) is the vertex f(x)=(x-2) 2 -1 For our function, h=2 and k=-1
  • 13. Example 1: Continued The result is now in vertex form: f(x)=(x-2) 2 +(-1) f(x)=(x-h) 2 +k where ( h , k ) is the vertex f(x)=(x-2) 2 -1 For our function, h=2 and k=-1 Therefore, the vertex is ( 2 , -1 )
  • 14. Example 1: Completed Here is the graph of f(x)=x 2 -4x+3 Vertex is (2, -1)
  • 15. Example 2: To find the vertex of f(x)=-2x 2 -2x+1 Completing the Square if the coefficient of x 2 is not 1.
  • 16. Example 2: Continued To find the vertex of f(x)=-2x 2 -2x+1 f(x)=(-2x 2 -2 x )+1 Separate the x-terms
  • 17. Example 2: Continued To find the vertex of f(x)=-2x 2 -2x+1 f(x)=( -2 x 2 -2 x )+1 Factor out the coefficient of x 2 f(x)= -2 (x 2 + x )+1
  • 18. Example 2: Continued To find the vertex of f(x)=-2x 2 -2x+1 f(x)=(-2x 2 -2 x )+1 f(x)= -2 (x 2 + 1 x )+1 Square half of the coefficient of x ( ) 1 2 = __ 2 __ 4 1
  • 19. Example 2: Continued To find the vertex of f(x)=-2x 2 -2x+1 __ f(x)=(-2x 2 -2 x )+1 f(x)=-2(x 2 +1x )+1 ( ) 1 2 = 2 f(x)= -2(x 2 +x+ )+1 Add this constant inside the parentheses __ 4 1 __ 4 1
  • 20. Example 2: Continued To find the vertex of f(x)=-2x 2 -2x+1 __ f(x)=(-2x 2 -2 x )+1 f(x)=-2(x 2 +1x )+1 ( ) 1 2 = 2 f(x)= -2 (x 2 + x+ )+1 Notice we have really added -2 ( ) to the equation __ 4 1 __ 4 1 __ 4 1
  • 21. Example 2: Continued To find the vertex of f(x)=-2x 2 -2x+1 __ f(x)=(-2x 2 -2 x )+1 f(x)=-2(x 2 +1x )+1 ( ) 1 2 = 2 f(x)= -2 (x 2 + x+ )+1 -( -2 )( ) Therefore, subtract -2 ( ) to maintain the same equation __ 4 1 __ 4 1 __ 4 1 __ 4 1
  • 22. Example 2: Continued To find the vertex of f(x)=-2x 2 -2x+1 __ f(x)=(-2x 2 -2 x )+1 f(x)=-2(x 2 +1x )+1 ( ) 1 2 = 2 f(x)= -2(x 2 +x+ )+ 1-(-2)( ) Simplify f(x)= -2(x 2 +x+ )+ __ 4 1 __ 4 1 __ 4 1 __ 4 1 __ 2 3
  • 23. Example 2: Continued Now you are ready to Complete the Square! 3 f(x)= -2(x 2 +x+ )+ __ 4 1 __ 2
  • 24. Example 2: Continued Now you are ready to Complete the Square! 3 f(x)= -2( x 2 +x+ )+ __ 4 1 __ 2 The expression in the parentheses is a perfect square trinomial
  • 25. Example 2: Continued Now you are ready to Complete the Square! 3 f(x)= -2( x+ )( x + )+ f(x)= -2( x 2 +x+ )+ __ 4 1 __ 2 Factor it! __ 2 1 __ 2 1 __ 2 3
  • 26. Example 2: Continued Now you are ready to Complete the Square! 3 Simplify the right side f(x)= -2( x+ )( x + )+ f(x)=-2 ( x+ ) 2 + f(x)= -2(x 2 +x+ )+ __ 4 1 __ 2 __ 2 1 __ 2 1 __ 2 3 __ 2 3 __ 2 1
  • 27. Example 2: Continued The result is now in vertex form: f(x)=a(x-h) 2 +k where (h,k) is the vertex f(x)=-2 (x+ ) 2 + __ 2 3 __ 2 1
  • 28. Example 2: Continued The result is now in vertex form: f(x)=a(x-h) 2 +k where (h,k) is the vertex f(x)=-2 (x - ) 2 + Change addition to subtracting the opposite f(x)=-2 (x + ) 2 + __ 2 3 __ 2 - 1 __ 2 3 __ 2 1
  • 29. Example 2: Continued The result is now in vertex form: f(x)=a(x- h ) 2 + k where (h,k) is the vertex f(x)=-2 (x- ) 2 + For our function, h= and k= f(x)=-2 (x+ ) 2 + __ 2 3 __ 2 -1 __ 2 3 __ 2 -1 __ 2 3 __ 2 1
  • 30. Example 2: Continued The result is now in vertex form: f(x)=a(x-h) 2 +k where ( h , k ) is the vertex f(x)=-2 (x- ) 2 + For our function, h= and k= f(x)=-2 (x+ ) 2 + Therefore, the vertex is ( , ) __ 2 3 __ 2 -1 __ 2 3 __ 2 -1 __ 2 3 __ 2 1 __ 2 -1 __ 2 3
  • 31. Example 2: Completed Here is the graph of f(x)= -2x 2 -2x+1 Vertex is ( , ) __ 2 -1 __ 2 3