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Relativistic approach to speeds greater than c

Speeds greater than c are existed. then how to satisfy the Lorentz factor in Relativistic equation iis explained in this article on perception basis....Read more
Relativistic Approach to Speeds Beyond c. By Dadarao Dhone, Retd. EE, E&M, HP, Mumbai,then, Retd. Faculty from Engg. College. The speed of light is c w.r.t. its source and an observer attached to the source's frame. Tht speed of light w.r.t. the observed with respect to whom the source is moving at speed v, the speed of light is (c 2 - v 2 ) 1/2 as per my published papers and published copies submitted to You some months before. It is explained in my eBook published on Free-eBook.net, named, 'Special Relativity With Einstein' 2015. Below fact gives, how relativistic mathematics works at source speeds greater than c. Sir, here I remember my enote submitted to You a good time back before that, only mathematics and simulations doesn't do work sufficiently in research work; in addition perception of real facts should also be accompanied; then only real facts can be worked out in Research work. And to my gladness, I had confirming reply to it. Below is an example of it. The velocity of light w.r.t. its source as judged by observer is (c 2 - v 2 ) 1/2 . The statement that, velocity of light is constant in free space irrespective of any frame and relative motion between any frame is not true. The experiments give the velocity of light w.r.t. its source only and not w.r.t. any observer. Above velocity is w.r.t. observer, the velocity of light; when he intends to find it that what he will see the velocity of light . When the source is moving say at velocity 2c then the expression of velocity for the stationary observer becomes (c 2 - 4c 2 ) 1/2 light will be travelling towards us at velocity c w.r.t. source and the source is travelling at velocity 2c away from us. But for observer i.e. for us, the source is travelling away from us at speed 2c. Hence the light photons will also be travelling away from us at a velocity smaller than 2c. The velocity of light is reversed hence we have to reverse the signs of the quantities in the bracket. Hence, velocity of light in this case comes as (- c 2 + 4c 2 ) 1/2 that is equal to (3c 2 ) 1/2 i.e. equal to (1.732).c. In this Brain experiment, the light released by the source also is trailing behind the source and not travelling towards the observer assumed stationary representing us. This exersize also reveals what is meant by an imaginary quantity in mathematics. While dealing reality, how some of it result becomes imaginary non-perceivable. No it cannot be. The imaginary quantity must have some perceivable meaning. Imaginary quantity can be perceived as true one, by observing, by perceiving the resultant quantities, reversing them, and then observing and perceiving their resultant real quantity. The space/line contraction and time dilation phenomena will also be reversed In place of contraction it will be observed elongation and in place of dilation it will be observed contraction.
Relativistic Approach to Speeds Beyond c. By Dadarao Dhone, Retd. EE, E&M, HP, Mumbai,then, Retd. Faculty from Engg. College. The speed of light is c w.r.t. its source and an observer attached to the source's frame. Tht speed of light w.r.t. the observed with respect to whom the source is moving at speed v, the speed of light is (c2 - v2)1/2 as per my published papers and published copies submitted to You some months before. It is explained in my eBook published on Free-eBook.net, named, 'Special Relativity With Einstein' 2015. Below fact gives, how relativistic mathematics works at source speeds greater than c. Sir, here I remember my enote submitted to You a good time back before that, only mathematics and simulations doesn't do work sufficiently in research work; in addition perception of real facts should also be accompanied; then only real facts can be worked out in Research work. And to my gladness, I had confirming reply to it. Below is an example of it. The velocity of light w.r.t. its source as judged by observer is (c2 - v2)1/2 . The statement that, velocity of light is constant in free space irrespective of any frame and relative motion between any frame is not true. The experiments give the velocity of light w.r.t. its source only and not w.r.t. any observer. Above velocity is w.r.t. observer, the velocity of light; when he intends to find it that what he will see the velocity of light . When the source is moving say at velocity 2c then the expression of velocity for the stationary observer becomes (c2 - 4c2) 1/2 light will be travelling towards us at velocity c w.r.t. source and the source is travelling at velocity 2c away from us. But for observer i.e. for us, the source is travelling away from us at speed 2c. Hence the light photons will also be travelling away from us at a velocity smaller than 2c. The velocity of light is reversed hence we have to reverse the signs of the quantities in the bracket. Hence, velocity of light in this case comes as (- c2 + 4c2)1/2 that is equal to (3c2)1/2 i.e. equal to (1.732).c. In this Brain experiment, the light released by the source also is trailing behind the source and not travelling towards the observer assumed stationary representing us. This exersize also reveals what is meant by an imaginary quantity in mathematics. While dealing reality, how some of it result becomes imaginary non-perceivable. No it cannot be. The imaginary quantity must have some perceivable meaning. Imaginary quantity can be perceived as true one, by observing, by perceiving the resultant quantities, reversing them, and then observing and perceiving their resultant real quantity. The space/line contraction and time dilation phenomena will also be reversed In place of contraction it will be observed elongation and in place of dilation it will be observed contraction.
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