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IB Chemistry Power Points


                              Topic 05
                             Energetics

www.pedagogics.ca
                            Lesson
                       Exothermic and
                    Endothermic Reactions
                       and Calorimetry
Much taken from

ENTHALPY
 CHANGES




             Great thanks to
JONATHAN HOPTON & KNOCKHARDY PUBLISHING
     www.knockhardy.org.uk/sci.htm
Background and Review
First Law of Thermodynamics (Law of Energy Conservation)
Energy can be neither created nor destroyed but it can be converted from one
form to another

Energy Changes in Chemical Reactions

All chemical reactions are accompanied by some form of energy change

                Exothermic        Energy is given out

                Endothermic       Energy is absorbed


Examples        Exothermic        combustion reactions
                                  neutralization (acid + base)

                Endothermic       photosynthesis
                                  thermal decomposition of calcium carbonate

              Activity : observing exothermic and endothermic reactions
Key Concept

The heat content of a chemical system is called
enthalpy (represented by H).

   We cannot measure enthalpy directly, only
   the change in enthalpy ∆H i.e. the amount of
   heat released or absorbed when a chemical
   reaction occurs at constant pressure.

              ∆H = H(products) – H(reactants)

 ∆Ho (the STANDARD enthalpy of reaction) is the
 value measured when temperature is 298 K and
 pressure is 101.3 kPa.
Enthalpy Diagram -Exothermic Change

 If ∆H is negative, H(products) < H(reactants)
 There is an enthalpy decrease and heat is
 released to the surroundings.

enthalpy
Enthalpy Diagram - Endothermic Change

If ∆H is positive, H(products) > H(reactants)
There is an enthalpy increase and heat is
absorbed from the surroundings.


enthalpy
Example: Enthalpy change in a chemical reaction

       Exothermic reactions release heat

      N2(g) + 3H2(g)  2 NH3(g)
                                  ∆H = -92.4 kJ/mol



                         The coefficients in the
                         balanced equation
                         represent the number of
                         moles of reactants and
                         products.
N2(g) + 3H2(g)  2 NH3(g)
                                  ∆H = -92.4 kJ/mol

State symbols are ESSENTIAL as changes of state
involve changes in thermal energy.


 The enthalpy change is directly proportional to the
 number of moles of substance involved in the reaction.



   For the above equation, 92.4 kJ is released
   - for each mole of N2 reacted
   - for every 3 moles of H2 reacted
   - for every 2 moles of NH3 produced.
The reverse reaction
2 NH3(g)  N2(g) + 3H2(g)
                            ∆H = +92.4 kJ/mol


                       Note: the enthalpy
                       change can be read
                       directly from the
                       enthalpy profile diagram.
Thermochemical Standard Conditions
The ∆H value for a given reaction will depend
on reaction conditions.

Values for enthalpy changes are standardized :


for the standard enthalpy ∆Ho
-Temperature is 298 K
- Pressure is 1 atmosphere
- All solutions involved are 1 M concentration
Assigned : Review Exercise 1

  The ∆H value for a given reaction will depend
  on reaction conditions.

  Values for enthalpy changes are standardized :


  for the standard enthalpy ∆Ho
  -Temperature is 298 K
  - Pressure is 1 atmosphere
  - All solutions involved are 1 M concentration
Calorimetry – Part 1

  Specific Heat Capacity
The specific heat capacity of a substance is a physical
property. It is defined as the amount of heat (Joules)
required to change the temperature (oC or K) of a unit
mass (g or kg) of substance by ONE degree.


  Specific heat capacity (SHC) is measured in
  J g-1 K-1 or kJ kg-1 K-1 (chemistry)
  J kg-1 K-1 (physics)
Calorimetry – continued

Heat and temperature change
Knowing the SHC is useful in thermal chemistry. Heat
added or lost can be determined by measuring
temperature change of a known substance (water).

                Q = mc∆T

      heat = mass x SHC x ∆Temp
Determining the Specific Heat Capacity of Water

 Read the background information and lab
 activity instructions carefully

A kettle (and other electrical heating devices) have
power ratings (given in Watts). This tells you the
amount of heat energy supplied by the device. The
watt is equivalent to 1 J per second.


                (heat) Q = P x t

  DON’T FORGET TO CONSIDER UNCERTAINTY
Determining the Specific Heat Capacity of Water

What you need to do (DCP)
Plot data and choose a suitable range for analysis
(look for constant increase in temperature)
Organize the data from the range in a suitable table.
You may choose to do further processing at this time.
Plot the selected range of raw/processed data. Use
the slope to determine the specific heat capacity of
water.
Present all calculations / data processing clearly

   DON’T FORGET TO CONSIDER UNCERTAINTY
Determining the Specific Heat Capacity of Water

What you need to do (CE)
Write a conclusion paragraph. Don’t forget to
compare data to the accepted value. Mention any
indication of presence (or absence) of random or
systematic error. Is your result valid?

Brainstorm a list of procedural/measurement
weaknesses or limitations.
-do you have evidence (data) that any of these
significantly affected the result (as indicated by the
data)? How could you improve the investigation?

Be prepared to discuss in class
Determining Specific Heat Capacity of Water

Sample results
1300 W kettle
supplies 1300 J of
heat each second.

1300 J heat gives                Slope tells us
∆T of 0.2215 oC                  temperature
                                 increases
                                 0.2215 oC each
A ∆T of 1oC would                second.
therefore require
5870 J of heat.
Determining Specific Heat Capacity of Water

Sample results (continued)
Mass of water in kettle was 1405 g. To change the temperature
of this water by 1 degree, 5870 J of heat were required.


  The amount of heat required to change 1 g of water is
  therefore 4.18 J. This is the SHC of water (very close to the
  literature value)


         SHC of H2O is 4.18 J g-1 K-1
For example
When 3 g of sodium carbonate are added to 50 cm3 of
1.0 M HCl, the temperature rises from 22 °C to 28.5 °C.
Calculate the heat required for this temperature change.
Calorimetry – Part 2


Applications
A calorimeter is used to
measure the heat
absorbed or released in
a chemical (or other)
process by measuring
the temperature change
of an insulated mass of
water.
Sample Problem 1
When 3 g of sodium carbonate are added to 50 cm3 of
1.0 M HCl, the temperature rises from 22.0 C to 28.5 C.
Calculate the heat required for this temperature change.
3                 -3
Sample problem 2: 50.0 cm of a 1.00 mol dm HCl solution is mixed with 25.0
   3                -3
cm of 2.00 mol dm NaOH. A neutralization reaction occurs. The initial
                                       o
temperature of both solutions was 26.7 C. After stirring and accounting for
                                                     o
heat loss, the highest temperature reached was 33.5 C. Calculate the enthalpy
change for this reaction.




                      NaOH                            HCl
                                                      both 26.7o
                      .




                                                     26.7o  33.5o
3                 -3
Sample problem 2: 50.0 cm of a 1.00 mol dm HCl solution is mixed with 25.0
   3                -3
cm of 2.00 mol dm NaOH. A neutralization reaction occurs. The initial
                                       o
temperature of both solutions was 26.7 C. After stirring and accounting for
                                                     o
heat loss, the highest temperature reached was 33.5 C. Calculate the enthalpy
change for this reaction.




After writing a balanced equation, the molar quantities and
limiting reactant needs to be determined.




Note that in this example there is exactly the right amount of
each reactant. If one reactant is present in excess, the heat
evolved will associated with the mole amount of limiting reactant.
3                 -3
Sample problem 2: 50.0 cm of a 1.00 mol dm HCl solution is mixed with 25.0
   3                -3
cm of 2.00 mol dm NaOH. A neutralization reaction occurs. The initial
                                       o
temperature of both solutions was 26.7 C. After stirring and accounting for
                                                     o
heat loss, the highest temperature reached was 33.5 C. Calculate the enthalpy
change for this reaction.




Next step – determine how much heat was released.




There are some assumptions in this calculation
- Density of reaction mixture (to determine mass)
- SHC of reaction mixture (to calculate Q)
3                 -3
Sample problem 2: 50.0 cm of a 1.00 mol dm HCl solution is mixed with 25.0
   3                -3
cm of 2.00 mol dm NaOH. A neutralization reaction occurs. The initial
                                       o
temperature of both solutions was 26.7 C. After stirring and accounting for
                                                     o
heat loss, the highest temperature reached was 33.5 C. Calculate the enthalpy
change for this reaction.




Final step – calculate ΔH for the reaction
Sample problem 3: to determine the enthalpy of combustion for ethanol (see
reaction), a calorimeter setup (below) was used. The burner was lit and allowed
to heat the water for 60 s. The change in mass of the burner was 0.518 g and
                                                    o
the temperature increase was measured to be 9.90 C.




                                                    What is the big
                                                    assumption made
                                                    with this type of
                                                    experiment?
Sample problem 3: to determine the enthalpy of combustion for ethanol (see
reaction), a calorimeter setup (below) was used. The burner was lit and allowed
to heat the water for 60 s. The change in mass of the burner was 0.518 g and
                                                    o
the temperature increase was measured to be 9.90 C.




First step – calculate heat evolved using calorimetry
Last step – determine ΔH for the reaction
3                 -3
Sample problem 4: 100.0 cm of 0.100 mol dm copper II sulphate solution is
placed in a styrofoam cup. 1.30 g of powdered zinc is added and a single
replacement reaction occurs. The temperature of the solution over time is
shown in the graph below. Determine the enthalpy value for this reaction.



                                           First step
                                           Make sure you understand
                                           the graph.


                                           Extrapolate to determine
                                           the change in
                                           temperature.



The extrapolation is necessary to compensate for heat loss while the reaction
is occurring. Why would powdered zinc be used?
3                -3
Sample problem 4: 100.0 cm of 0.100 mol dm copper II sulphate solution is
placed in a styrofoam cup. 1.30 g of powdered zinc is added and a single
replacement reaction occurs. The temperature of the solution over time is
shown in the graph below. Determine the enthalpy value for this reaction.




Determine the limiting reactant


Calculate Q


Calculate the enthalpy for the reaction.




                                                      Review Exercise 2

More Related Content

Lesson : Enthalpy and Calorimetry

  • 1. IB Chemistry Power Points Topic 05 Energetics www.pedagogics.ca Lesson Exothermic and Endothermic Reactions and Calorimetry
  • 2. Much taken from ENTHALPY CHANGES Great thanks to JONATHAN HOPTON & KNOCKHARDY PUBLISHING www.knockhardy.org.uk/sci.htm
  • 3. Background and Review First Law of Thermodynamics (Law of Energy Conservation) Energy can be neither created nor destroyed but it can be converted from one form to another Energy Changes in Chemical Reactions All chemical reactions are accompanied by some form of energy change Exothermic Energy is given out Endothermic Energy is absorbed Examples Exothermic combustion reactions neutralization (acid + base) Endothermic photosynthesis thermal decomposition of calcium carbonate Activity : observing exothermic and endothermic reactions
  • 4. Key Concept The heat content of a chemical system is called enthalpy (represented by H). We cannot measure enthalpy directly, only the change in enthalpy ∆H i.e. the amount of heat released or absorbed when a chemical reaction occurs at constant pressure. ∆H = H(products) – H(reactants) ∆Ho (the STANDARD enthalpy of reaction) is the value measured when temperature is 298 K and pressure is 101.3 kPa.
  • 5. Enthalpy Diagram -Exothermic Change If ∆H is negative, H(products) < H(reactants) There is an enthalpy decrease and heat is released to the surroundings. enthalpy
  • 6. Enthalpy Diagram - Endothermic Change If ∆H is positive, H(products) > H(reactants) There is an enthalpy increase and heat is absorbed from the surroundings. enthalpy
  • 7. Example: Enthalpy change in a chemical reaction Exothermic reactions release heat N2(g) + 3H2(g)  2 NH3(g) ∆H = -92.4 kJ/mol The coefficients in the balanced equation represent the number of moles of reactants and products.
  • 8. N2(g) + 3H2(g)  2 NH3(g) ∆H = -92.4 kJ/mol State symbols are ESSENTIAL as changes of state involve changes in thermal energy. The enthalpy change is directly proportional to the number of moles of substance involved in the reaction. For the above equation, 92.4 kJ is released - for each mole of N2 reacted - for every 3 moles of H2 reacted - for every 2 moles of NH3 produced.
  • 9. The reverse reaction 2 NH3(g)  N2(g) + 3H2(g) ∆H = +92.4 kJ/mol Note: the enthalpy change can be read directly from the enthalpy profile diagram.
  • 10. Thermochemical Standard Conditions The ∆H value for a given reaction will depend on reaction conditions. Values for enthalpy changes are standardized : for the standard enthalpy ∆Ho -Temperature is 298 K - Pressure is 1 atmosphere - All solutions involved are 1 M concentration
  • 11. Assigned : Review Exercise 1 The ∆H value for a given reaction will depend on reaction conditions. Values for enthalpy changes are standardized : for the standard enthalpy ∆Ho -Temperature is 298 K - Pressure is 1 atmosphere - All solutions involved are 1 M concentration
  • 12. Calorimetry – Part 1 Specific Heat Capacity The specific heat capacity of a substance is a physical property. It is defined as the amount of heat (Joules) required to change the temperature (oC or K) of a unit mass (g or kg) of substance by ONE degree. Specific heat capacity (SHC) is measured in J g-1 K-1 or kJ kg-1 K-1 (chemistry) J kg-1 K-1 (physics)
  • 13. Calorimetry – continued Heat and temperature change Knowing the SHC is useful in thermal chemistry. Heat added or lost can be determined by measuring temperature change of a known substance (water). Q = mc∆T heat = mass x SHC x ∆Temp
  • 14. Determining the Specific Heat Capacity of Water Read the background information and lab activity instructions carefully A kettle (and other electrical heating devices) have power ratings (given in Watts). This tells you the amount of heat energy supplied by the device. The watt is equivalent to 1 J per second. (heat) Q = P x t DON’T FORGET TO CONSIDER UNCERTAINTY
  • 15. Determining the Specific Heat Capacity of Water What you need to do (DCP) Plot data and choose a suitable range for analysis (look for constant increase in temperature) Organize the data from the range in a suitable table. You may choose to do further processing at this time. Plot the selected range of raw/processed data. Use the slope to determine the specific heat capacity of water. Present all calculations / data processing clearly DON’T FORGET TO CONSIDER UNCERTAINTY
  • 16. Determining the Specific Heat Capacity of Water What you need to do (CE) Write a conclusion paragraph. Don’t forget to compare data to the accepted value. Mention any indication of presence (or absence) of random or systematic error. Is your result valid? Brainstorm a list of procedural/measurement weaknesses or limitations. -do you have evidence (data) that any of these significantly affected the result (as indicated by the data)? How could you improve the investigation? Be prepared to discuss in class
  • 17. Determining Specific Heat Capacity of Water Sample results 1300 W kettle supplies 1300 J of heat each second. 1300 J heat gives Slope tells us ∆T of 0.2215 oC temperature increases 0.2215 oC each A ∆T of 1oC would second. therefore require 5870 J of heat.
  • 18. Determining Specific Heat Capacity of Water Sample results (continued) Mass of water in kettle was 1405 g. To change the temperature of this water by 1 degree, 5870 J of heat were required. The amount of heat required to change 1 g of water is therefore 4.18 J. This is the SHC of water (very close to the literature value) SHC of H2O is 4.18 J g-1 K-1
  • 19. For example When 3 g of sodium carbonate are added to 50 cm3 of 1.0 M HCl, the temperature rises from 22 °C to 28.5 °C. Calculate the heat required for this temperature change.
  • 20. Calorimetry – Part 2 Applications A calorimeter is used to measure the heat absorbed or released in a chemical (or other) process by measuring the temperature change of an insulated mass of water.
  • 21. Sample Problem 1 When 3 g of sodium carbonate are added to 50 cm3 of 1.0 M HCl, the temperature rises from 22.0 C to 28.5 C. Calculate the heat required for this temperature change.
  • 22. 3 -3 Sample problem 2: 50.0 cm of a 1.00 mol dm HCl solution is mixed with 25.0 3 -3 cm of 2.00 mol dm NaOH. A neutralization reaction occurs. The initial o temperature of both solutions was 26.7 C. After stirring and accounting for o heat loss, the highest temperature reached was 33.5 C. Calculate the enthalpy change for this reaction. NaOH HCl both 26.7o . 26.7o  33.5o
  • 23. 3 -3 Sample problem 2: 50.0 cm of a 1.00 mol dm HCl solution is mixed with 25.0 3 -3 cm of 2.00 mol dm NaOH. A neutralization reaction occurs. The initial o temperature of both solutions was 26.7 C. After stirring and accounting for o heat loss, the highest temperature reached was 33.5 C. Calculate the enthalpy change for this reaction. After writing a balanced equation, the molar quantities and limiting reactant needs to be determined. Note that in this example there is exactly the right amount of each reactant. If one reactant is present in excess, the heat evolved will associated with the mole amount of limiting reactant.
  • 24. 3 -3 Sample problem 2: 50.0 cm of a 1.00 mol dm HCl solution is mixed with 25.0 3 -3 cm of 2.00 mol dm NaOH. A neutralization reaction occurs. The initial o temperature of both solutions was 26.7 C. After stirring and accounting for o heat loss, the highest temperature reached was 33.5 C. Calculate the enthalpy change for this reaction. Next step – determine how much heat was released. There are some assumptions in this calculation - Density of reaction mixture (to determine mass) - SHC of reaction mixture (to calculate Q)
  • 25. 3 -3 Sample problem 2: 50.0 cm of a 1.00 mol dm HCl solution is mixed with 25.0 3 -3 cm of 2.00 mol dm NaOH. A neutralization reaction occurs. The initial o temperature of both solutions was 26.7 C. After stirring and accounting for o heat loss, the highest temperature reached was 33.5 C. Calculate the enthalpy change for this reaction. Final step – calculate ΔH for the reaction
  • 26. Sample problem 3: to determine the enthalpy of combustion for ethanol (see reaction), a calorimeter setup (below) was used. The burner was lit and allowed to heat the water for 60 s. The change in mass of the burner was 0.518 g and o the temperature increase was measured to be 9.90 C. What is the big assumption made with this type of experiment?
  • 27. Sample problem 3: to determine the enthalpy of combustion for ethanol (see reaction), a calorimeter setup (below) was used. The burner was lit and allowed to heat the water for 60 s. The change in mass of the burner was 0.518 g and o the temperature increase was measured to be 9.90 C. First step – calculate heat evolved using calorimetry Last step – determine ΔH for the reaction
  • 28. 3 -3 Sample problem 4: 100.0 cm of 0.100 mol dm copper II sulphate solution is placed in a styrofoam cup. 1.30 g of powdered zinc is added and a single replacement reaction occurs. The temperature of the solution over time is shown in the graph below. Determine the enthalpy value for this reaction. First step Make sure you understand the graph. Extrapolate to determine the change in temperature. The extrapolation is necessary to compensate for heat loss while the reaction is occurring. Why would powdered zinc be used?
  • 29. 3 -3 Sample problem 4: 100.0 cm of 0.100 mol dm copper II sulphate solution is placed in a styrofoam cup. 1.30 g of powdered zinc is added and a single replacement reaction occurs. The temperature of the solution over time is shown in the graph below. Determine the enthalpy value for this reaction. Determine the limiting reactant Calculate Q Calculate the enthalpy for the reaction. Review Exercise 2