JEE Physics/ Lakshmikanta Satapathy/ Direct Current QA part 9/ Question on Power consumed by an external resistance connected across a parallel combination of two identical cells
1. Physics Helpline
L K Satapathy
Direct Current - 9
Power consumed by External Resistance
rE
R
rE
2. Physics Helpline
L K Satapathy
Direct Current - 9
Cells in Parallel
Question : Two identical cells, each of emf 2 V and internal
resistance 1 are connected to an external resistance R =
0.5 as shown in the figure. Then the power consumed by
the resistance R is
(a) 0.9 W (b) 1.25 W (c) 1.75 W (d) 2 W
12V
0. 5 R
12V
Answer :
When two identical cells each of emf E and internal resistance r are connected in
parallel across an external resistance R , then the net emf = E
Total internal resistance
2
r
External resistance = R
Total circuit resistance
2
r
R
Circuit current
2
2
2
E E
I
r R rR
E
E
r
r
R
3. Physics Helpline
L K Satapathy
Direct Current - 9
Cells in Parallel
Correct option = (d)
Given: E = 2 V and r = 1
The two cells are in parallel The net emf = 2 V
Total internal resistance 0.5
2
r
0.52V
0.5
Total circuit resistance 0.5 0.5 1
Current through external resistance
2
2
1
I A
Power consumed by external resistance 2
4 0.5 2P I R W
External resistance 0.5
4. Physics Helpline
L K Satapathy
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